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27 Dec 2024, 02:38
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Hello,
Line A: Maximum 42 hours
Line B: Maximum 20 hours
Line C: Maximum 12 hours
condition is that it should be more than half maximum
Line A: 0.5*42=21
Line B: 0.5*20=10
Line C: 0.5*12=6
we have to distribute 45 hours
currently as per condition we have total 37 (21+10+6) hours
we have currently need to adjust 8 hours
B can 16 or 17
if B is 16 then we can have 22 hours for A and 7 hours for C
if B is 17 then either we can have A as 22 or C as 7 both is not possible
Hence B 16 and C is 7 and A will be 22 all satisfy the condition
I hope it helps and if you like it please give kudos
Line A: Maximum 42 hours
Line B: Maximum 20 hours
Line C: Maximum 12 hours
condition is that it should be more than half maximum
Line A: 0.5*42=21
Line B: 0.5*20=10
Line C: 0.5*12=6
we have to distribute 45 hours
currently as per condition we have total 37 (21+10+6) hours
we have currently need to adjust 8 hours
B can 16 or 17
if B is 16 then we can have 22 hours for A and 7 hours for C
if B is 17 then either we can have A as 22 or C as 7 both is not possible
Hence B 16 and C is 7 and A will be 22 all satisfy the condition
I hope it helps and if you like it please give kudos
27 Dec 2024, 03:34
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Hi All,
Tyring to find value for C from the options,
C should be at minimun 7 as given that " Each line must receive more than half its maximum"
if C=7, then A+B= 38,
A should be minimum 22,therefore max value for B =38-22= 16
we do have an option for 16 hence our answer.
We can also try for when C=8, then A+B=37
A should be minimun 22, thereofre max value for B=37-22= 15
15 is not the option therefore rejected.
Therefore our answer B=16 and C=7
Tyring to find value for C from the options,
C should be at minimun 7 as given that " Each line must receive more than half its maximum"
if C=7, then A+B= 38,
A should be minimum 22,therefore max value for B =38-22= 16
we do have an option for 16 hence our answer.
We can also try for when C=8, then A+B=37
A should be minimun 22, thereofre max value for B=37-22= 15
15 is not the option therefore rejected.
Therefore our answer B=16 and C=7
27 Dec 2024, 03:46
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From the provided info:
21 < a <= 42
10 < b <= 20 . So b can only be 16 or 17 (1)
6 < c <= 12 . So c can only be 7 or 8 (2)
a + b + c = 45. Since min a = 22, max b + c = 45-22 = 23. From (1) & (2), we only have 1 option for this case: b = 16 and c = 7.
21 < a <= 42
10 < b <= 20 . So b can only be 16 or 17 (1)
6 < c <= 12 . So c can only be 7 or 8 (2)
a + b + c = 45. Since min a = 22, max b + c = 45-22 = 23. From (1) & (2), we only have 1 option for this case: b = 16 and c = 7.
