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27 Dec 2024, 02:38
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Hello,
Line A: Maximum 42 hours
Line B: Maximum 20 hours
Line C: Maximum 12 hours
condition is that it should be more than half maximum
Line A: 0.5*42=21
Line B: 0.5*20=10
Line C: 0.5*12=6
we have to distribute 45 hours
currently as per condition we have total 37 (21+10+6) hours
we have currently need to adjust 8 hours
B can 16 or 17
if B is 16 then we can have 22 hours for A and 7 hours for C
if B is 17 then either we can have A as 22 or C as 7 both is not possible
Hence B 16 and C is 7 and A will be 22 all satisfy the condition
I hope it helps and if you like it please give kudos
Line A: Maximum 42 hours
Line B: Maximum 20 hours
Line C: Maximum 12 hours
condition is that it should be more than half maximum
Line A: 0.5*42=21
Line B: 0.5*20=10
Line C: 0.5*12=6
we have to distribute 45 hours
currently as per condition we have total 37 (21+10+6) hours
we have currently need to adjust 8 hours
B can 16 or 17
if B is 16 then we can have 22 hours for A and 7 hours for C
if B is 17 then either we can have A as 22 or C as 7 both is not possible
Hence B 16 and C is 7 and A will be 22 all satisfy the condition
I hope it helps and if you like it please give kudos
27 Dec 2024, 03:34
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Bookmarks
Hi All,
Tyring to find value for C from the options,
C should be at minimun 7 as given that " Each line must receive more than half its maximum"
if C=7, then A+B= 38,
A should be minimum 22,therefore max value for B =38-22= 16
we do have an option for 16 hence our answer.
We can also try for when C=8, then A+B=37
A should be minimun 22, thereofre max value for B=37-22= 15
15 is not the option therefore rejected.
Therefore our answer B=16 and C=7
Tyring to find value for C from the options,
C should be at minimun 7 as given that " Each line must receive more than half its maximum"
if C=7, then A+B= 38,
A should be minimum 22,therefore max value for B =38-22= 16
we do have an option for 16 hence our answer.
We can also try for when C=8, then A+B=37
A should be minimun 22, thereofre max value for B=37-22= 15
15 is not the option therefore rejected.
Therefore our answer B=16 and C=7
27 Dec 2024, 03:46
Kudos
Bookmarks
From the provided info:
21 < a <= 42
10 < b <= 20 . So b can only be 16 or 17 (1)
6 < c <= 12 . So c can only be 7 or 8 (2)
a + b + c = 45. Since min a = 22, max b + c = 45-22 = 23. From (1) & (2), we only have 1 option for this case: b = 16 and c = 7.
21 < a <= 42
10 < b <= 20 . So b can only be 16 or 17 (1)
6 < c <= 12 . So c can only be 7 or 8 (2)
a + b + c = 45. Since min a = 22, max b + c = 45-22 = 23. From (1) & (2), we only have 1 option for this case: b = 16 and c = 7.
27 Dec 2024, 04:02
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Bookmarks
A plant must distribute 45 hours weekly among three production lines: A, B, and C.
Each line must receive more than half its maximum, all 45 hours must be used, and the number of hours allocated to each line must be an integer.
Select for Line B the hours that could have been allocated to Line B, and select for Line C the hours that could have been allocated to Line C that would be jointly consistent with the given information. Make only two selections, one in each column.
Each line must receive more than half its maximum and must be an integer.
So, A must receive, 42/2+1=22
Now, we are left with, 45-22=23 hours.
C must receive, 12/2+1=7, then B can receive 23-7=16.
Answer: B=16, C=7.
- Line A: Maximum 42 hours
- Line B: Maximum 20 hours
- Line C: Maximum 12 hours
Each line must receive more than half its maximum, all 45 hours must be used, and the number of hours allocated to each line must be an integer.
Select for Line B the hours that could have been allocated to Line B, and select for Line C the hours that could have been allocated to Line C that would be jointly consistent with the given information. Make only two selections, one in each column.
Each line must receive more than half its maximum and must be an integer.
So, A must receive, 42/2+1=22
Now, we are left with, 45-22=23 hours.
C must receive, 12/2+1=7, then B can receive 23-7=16.
Answer: B=16, C=7.
