Bunuel
12 Days of Christmas 2024 - 2025 Competition with $40,000 of Prizes
A plant must distribute 45 hours weekly among three production lines: A, B, and C.
- Line A: Maximum 42 hours
- Line B: Maximum 20 hours
- Line C: Maximum 12 hours
Each line must receive more than half its maximum, all 45 hours must be used, and the number of hours allocated to each line must be an integer.
Select for
Line B the hours that could have been allocated to Line B, and select for
Line C the hours that could have been allocated to Line C
that would be jointly consistent with the given information. Make only two selections, one in each column.
Total weekly hours: 45
Line A maximum: 42 hours
Line B maximum: 20 hours
Line C maximum: 12 hours
Each line must receive more than half its maximum hours.
Line A:
Minimum hours for Line A: 42 / 2 = 21 hours
Since the total hours is 45, Line A cannot receive its maximum of 42 hours.
Therefore, Line A must receive between 21 and 41 hours.
Line B:
Minimum hours for Line B: 20 / 2 = 10 hours
Maximum hours for Line B: 20 hours
Line C:
Minimum hours for Line C: 12 / 2 = 6 hours
Maximum hours for Line C: 12 hours
Possible Allocations:We need to find combinations of hours for Line B and Line C that satisfy the constraints and add up to the total hours (45) when combined with the hours allocated to Line A.
Let's consider some possibilities:
Line B = 16 hours, Line C = 6 hours:
This combination satisfies the minimum and maximum hours for both lines.
Assuming Line A receives 23 hours (within its allowed range), the total hours would be 16 + 6 + 23 = 45.
Line B = 17 hours, Line C = 7 hours:
This combination also satisfies the minimum and maximum hours for both lines.
Assuming Line A receives 21 hours (its minimum), the total hours would be 17 + 7 + 21 = 45.
Therefore, the possible allocations for Line B and Line C are:
Line B: 16 hours
Line C: 6 hours
Line B: 17 hours
Line C: 7 hoursIMOLine B: 16Line C: 7