A racecar driver has completed 12 1/2 laps of a 50 lap race.

Question

A racecar driver has completed  12 \frac{1}{2}  laps of a 50 lap race. What fractional part of the race remains?

A. 1/4
B. 1/5
C. 3/4
D. 4/5
E. 75/2

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ManifestDreamMBA · Answer

Total laps = 50
Laps completed =  12 \frac{1}{2}  =   \frac{25}{2} 
Laps remaining = 50 -25/2 = 75/2

Fractional part of the race remaining = (75/2)/50 = 3/4

GMATinsight · Answer

Race = 50
completed = 12.5

Remaining = 50-12.5 = 37.5

Fraction that remains = 37.5/50 = 3/4

Answer: Option C

ddm1811 · Answer

in 50 laps ... 25/2 is completed 
similarly in 100 laps .... 25 will be completed

remaining laps = 75 => 3/4  option C

Ayeka · Answer

Total Laps= 50
Completed laps= 12.5 
Remaining laps= 50-12.5=37.5 
Required fraction= 37.5/50=375/500=3/4

Answer: C

Dereno · Answer

Given that A racecar driver has completed  12 \frac{1}{2}  laps of a 50 lap race.

lets convert the mixed fraction  12 \frac{1}{2}  into improper fraction = 25/2 .

laps remaining = 50 - (25/2) = 75/2.

fraction remaining = (75/2)  /  50

= (25*3)  / (2*25*2)

= 3/4

option C

Abhiswarup · Answer

Race completed =12.5 Laps
Remaining = 37.5= 37.5/50= 3/4
Answer is C.

rohitz98 · Answer

Given 12.5 out of 50 km have been completed in the race
12.5/50 gives 1/4
Hence 3/4 of race remains  Option C

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