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Let John, Allen, and Frank initially have $J, $A, and $F.

After the transactions:
John gives Allen 5:
John has $J - 5,
Allen has $A + 5.

Then Allen gives Frank 2:
Allen has $A + 5 - 2 = A + 3 Frank has $F + 2.
Given they all have the same amount in the end:

J - 5 = A + 3 = F + 2
From J - 5 = A + 3

J - A = 8
So John has 8 dollars more than Allen.
Therefore option E
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Bunuel
If John gives Allen 5 dollars and Allen gives Frank 2 dollars, the three boys will have the same amount of money. How much more money does John have than Allen?

A. $3
B. $5
C .$6
D. $7
E. $8


­
Let the initial amount with John, Allen and Frank be J, A and F respectively.

John gives Allen 5 dollars

J-5 = A+5

Allen gives Frank 2 dollars

A+5-2 = F+2 = A+3

The amounts are equal: J-5 = A+3 = F+2

J = A+8

J - A = 8

Option E
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Consider the initial amounts of john, allen and frank as j,a and f respectively
Now given j-5 = a+3 = f+2
So j = a+8
Hence john has 8 dollars more Option E
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