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arushi118
Joined: 21 Jul 2024
Last visit: 19 Apr 2026
Posts: 267
Given Kudos: 894
Location: India
Concentration: Leadership, General Management
Schools: INSEAD Aug '26 LBS '26 Kellogg '26
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16 Dec 2025, 03:21
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A: Probability of JOhn eating breakfast = 0.8
B: Prob of Mary doing yoga = p
let y = P(atleast 1) = P(A or B) = P(A) + P(B) - P(A and B)
P(A and B) = 0.8p as A and B are independent events
So y = 0.8 + p - 0.8p
y = 0.8+ 0.2p
p=0.5 and y = 0.9 from the options satisfy this.
B: Prob of Mary doing yoga = p
let y = P(atleast 1) = P(A or B) = P(A) + P(B) - P(A and B)
P(A and B) = 0.8p as A and B are independent events
So y = 0.8 + p - 0.8p
y = 0.8+ 0.2p
p=0.5 and y = 0.9 from the options satisfy this.
SSWTtoKellogg
Joined: 06 Mar 2024
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16 Dec 2025, 04:00
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Equation to solve : 0.8 + p - 0.8*p
Use, p = 0.5 ; then at least one = 0.9
Use, p = 0.5 ; then at least one = 0.9
16 Dec 2025, 05:14
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John has a 0.8 probability of eating breakfast with bacon and eggs, and Mary has a probability p of doing yoga in the morning.
Probability of John eating breakfast= 0.8
Probability of Mary doing yoga = p
The events are given to be independent
Also, P(atleast 1) = 1-P(neither)
P(neither) = (1-0.8)(1-p)= 0.2(1-p)
P(atleast 1)= 1-0.2(1-p) = 0.8+0.2p
Try to put the values of p given in choices
p=0.2 ; P(atleast1)= 0.84 ....not in options
p=0.4 ; P(atleast1)= 0.88.....not on option
p=0.5 ; P(atleast 1)=0.90 .....yes
P(atleast 1)=0.90
p=0.5
Probability of John eating breakfast= 0.8
Probability of Mary doing yoga = p
The events are given to be independent
Also, P(atleast 1) = 1-P(neither)
P(neither) = (1-0.8)(1-p)= 0.2(1-p)
P(atleast 1)= 1-0.2(1-p) = 0.8+0.2p
Try to put the values of p given in choices
p=0.2 ; P(atleast1)= 0.84 ....not in options
p=0.4 ; P(atleast1)= 0.88.....not on option
p=0.5 ; P(atleast 1)=0.90 .....yes
P(atleast 1)=0.90
p=0.5
