Bunuel
From the stem we can identify that this is a weighted average problem; we basically want to see if there's a weighted average scenario that forces us to use mango. It's also a yes or no question, so we can't get "maybe" as an answer.
\(sweetness=\frac{sugar}{weight}\)
Let's assign values to the sweetness of each fruit to make it easier to compare. Mango=3, Apple=2, Lemon=1.
Statement 1: Translation of statement is "average needs to be less than 2".
1 mango, 2 lemon: \(\frac{3+2}{3}=\frac{5}{3}<2\)
1 apple, 2 lemon: \(\frac{2+2}{3}=\frac{4}{3}<2\)
Answer to "is there mango in the salad" question is maybe. Therefore 1 is not sufficient.
Statement 2: Let's calculate the average of equal weights lemon and apple.
\(\frac{2+2+1+1}{4}=\frac{3}{2}\)
Can we get the sweetness above \(\frac{3}{2}\) using mango and not using mango? Let's see.
1 mango, 2 apple: \(\frac{3+2+2}{3}=\frac{7}{3}>\frac{3}{2}\)
2 apple, 1 lemon: \(\frac{2+2+1}{3}=\frac{5}{3}>\frac{3}{2}\)
Answer to "is there mango in the salad" question is maybe again. 2 is insufficient.
Statement 1 + 2:Putting them together, we essentially need to check, "can you make a salad with sweetness between 3/2 and 2 with mango and without mango?"
\(\frac{3}{2}<sweetness<2\)
Let's check.
1 mango, 2 lemon: \(\frac{3+1+1}{3}=\frac{5}{3}\), which satisfies the inequality.
2 apple, 1 lemon: \(\frac{2+2+1}{3}=\frac{5}{3}\), which satisfies the inequality.
Answer to "is there mango in the salad" question is maybe. Statements 1+2 are insufficient. Therefore E is the answer.