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25 Dec 2025, 05:27
Kudos
Bookmarks
We know that,
Dog runs from to park in 30 mins (9:00 - 9:30)
It plays in the park for 20 mins (9:30 - 9:50)
It then comes back with same speed and meets the man in 10 mins and they go back to parkl (9:50 - 10:00)
We need to find out when they reach the park together
We know that ,
Distance = Speed * Time
Let dog speed be x and man speed be y
Total distance be D
Since, distance is directly related to time
=> Total Distance of dog / Return distance of dog = Total time taken by dog while going from start to end / Total time taken by dog from end to meet man
=> D / Return distance = 30 / 10
=> Return distance = D/3
Dog meets man at point 2D/3 --------> (D - D/3 = 2D/3)
The man takes 60 mins to cover 2D/3 distance and reaches the point at 10AM
=> The man will take 30 more mins to cover the remaining D/3 distance and reach the park at 10:30 AM
D. 10:30 AM
Dog runs from to park in 30 mins (9:00 - 9:30)
It plays in the park for 20 mins (9:30 - 9:50)
It then comes back with same speed and meets the man in 10 mins and they go back to parkl (9:50 - 10:00)
We need to find out when they reach the park together
We know that ,
Distance = Speed * Time
Let dog speed be x and man speed be y
Total distance be D
Since, distance is directly related to time
=> Total Distance of dog / Return distance of dog = Total time taken by dog while going from start to end / Total time taken by dog from end to meet man
=> D / Return distance = 30 / 10
=> Return distance = D/3
Dog meets man at point 2D/3 --------> (D - D/3 = 2D/3)
The man takes 60 mins to cover 2D/3 distance and reaches the point at 10AM
=> The man will take 30 more mins to cover the remaining D/3 distance and reach the park at 10:30 AM
D. 10:30 AM
25 Dec 2025, 05:34
Kudos
Bookmarks
The sum of the distance the man travels in one hour and the distance the dog travels in 10 minutes (9:50 to 10:00) is the distance from home to park.
(speed of man)*1 + (speed of dog)*(1/6) = (distance from home to park)
Also we know that (speed of dog) = (distance from home to park)/(1/2) = 2*(distance from home to park). Susbtituting:
(speed of man) + 2*(distance from home to park)*(1/6) = (distance from home to park)
(speed of man) + (distance from home to park)*(1/3) = (distance from home to park)
(speed of man) = (distance from home to park)*(2/3)
time = (distance from home to park)/(speed of man) = 3/2 = 1.5 hour
9:00am + 1.5 hour = 10:30am
The correct answer is D
(speed of man)*1 + (speed of dog)*(1/6) = (distance from home to park)
Also we know that (speed of dog) = (distance from home to park)/(1/2) = 2*(distance from home to park). Susbtituting:
(speed of man) + 2*(distance from home to park)*(1/6) = (distance from home to park)
(speed of man) + (distance from home to park)*(1/3) = (distance from home to park)
(speed of man) = (distance from home to park)*(2/3)
time = (distance from home to park)/(speed of man) = 3/2 = 1.5 hour
9:00am + 1.5 hour = 10:30am
The correct answer is D
25 Dec 2025, 05:50
Kudos
Bookmarks
let the distance from home to park be x, which dog covers in 30 mins=1/2 hr.
speed of dog=x/(1/2)=2x per hour
after playing for 20 mins in park dog starts at 09:50 and meets his master at 10:00 AM
while the man continues to walk.
distance travelled by dog in 10 mins=2x*1/6=x/3
man has covered 2x/3 distance in an hour is his speed.
so together they will cover x/3 distance in (x/3)/(2x/3)=1/2 hour
so correct choice is 10:30 AM
speed of dog=x/(1/2)=2x per hour
after playing for 20 mins in park dog starts at 09:50 and meets his master at 10:00 AM
while the man continues to walk.
distance travelled by dog in 10 mins=2x*1/6=x/3
man has covered 2x/3 distance in an hour is his speed.
so together they will cover x/3 distance in (x/3)/(2x/3)=1/2 hour
so correct choice is 10:30 AM
