Adriens and his wife Camilles ages are in the ratio 5:4. In 6 years

Question

Adrien’s and his wife Camille’s ages are in the ratio 5:4. In 6 years, the ratio of their ages will be 11:9. At the time they got married, the ratio of their ages was 7:5. How old was Camille when they got married?

A. 18
B. 30
C. 36
D. 42
E. 48

A. 18
B. 30
C. 36
D. 42
E. 48

Dereno · Answer

The ratio of Adrien : Camellia age during marriage = 7:5.

so, Camellia age should be a multiple of 5.

Only option which matches the multiple of 5 is  30 .

Option B

Traditional method :

Adrien : Camillia = 5x : 4x

In 6 yrs, their ages will be

Adrien : Camillia = 5x +6 : 4x +6

The ratio of their ages equals 11:9.

5x+6 : 4x+6 :: 11:9

45x + 54 = 44x + 66

x = 12

The present ages of Adrien : Camillia = 5x : 4x = 60 : 48

Let the time of marriage be t.

Adrien : Camillia = 60 - t : 48 - t

(60-t) / (48-t) = 7/5

300 - 5t = 336 - 7t

t = 18.

Camillia age during marriage = 48-18 =  30.

Option B.

arushi118 · Answer

Currently:
A: 5x
C: 4x
Equation 1: (5x+6)/(4x+6) = 11/9
x=12

SO currently: A -> 60, C -> 48
Let them get married y years before:
(60-y)/(48-y) = 7/5
y = 18

SO C's age when they got married -> 48-18 = 30

vasu1104 · Answer

current age for A= 5p and C= 4p
in 6 years, ratio will be 11:9
so, 5p+6 / 4p +6 = (11/9)
solving this, we get p = 12

so currently A is 60 years old, C is 48 years old.
now when they got married the ratio was 7:5
say they got married x years ago.

60-x / 48-x =(7/5)
solving this we get x = 18
so when they got married, A was 42 and C was 30 years old.

option B

egmat · Answer

In age problems, the age DIFFERENCE between two people never changes.

Step 1: Find current ages 
Let Adrien's current age =  5x  and Camille's current age =  4x

In  6  years:
- Adrien will be  5x + 6 
- Camille will be  4x + 6

We're told this ratio equals  11:9 :

(5x + 6)/(4x + 6) = 11/9

Cross multiply:
9(5x + 6) = 11(4x + 6)
45x + 54 = 44x + 66
 x = 12

Current ages: 
- Adrien = 5(12) =  60 years 
- Camille = 4(12) =  48 years

Step 2: Find ages at marriage 
 The age difference is 60 - 48 =  12 years . This difference NEVER changes - not now, not in the future, not in the past.

At marriage, the ratio was  7:5 .
Let Adrien's age at marriage =  7y  and Camille's =  5y

The difference must still be  12 :
7y - 5y = 12
2y = 12
 y = 6

Camille's age at marriage = 5(6) =  30 years

Answer: B

Bunuel · Answer

GMAT Club Official Solution:

Let their current ages be 5x and 4x. Then (5x + 6)/(4x + 6) = 11/9, which gives x = 12, so their current ages are 60 and 48.

Let t be the number of years ago they got married. Then (60 - t)/(48 - t) = 7/5, which gives t = 18.

So Camille’s age at marriage was 48 - 18 = 30.

Answer: B.

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