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Arjunarocks
Joined: 20 Jun 2017
Last visit: 05 May 2018
Posts: 61
Own Kudos:
Given Kudos: 12
Location: India
Schools: ISB '20 Georgia Tech '20 (A$) Kelley '20 (A) Marshall '20 (A) Jones '20 (A$) Mendoza '20 (A)
GMAT 1: 720 Q50 V38
GPA: 4
Products:
Schools: ISB '20 Georgia Tech '20 (A$) Kelley '20 (A) Marshall '20 (A) Jones '20 (A$) Mendoza '20 (A)
GMAT 1: 720 Q50 V38
Posts: 61
Kudos:
13
25 Jun 2017, 07:54
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For those who dont like alligation method, here is a another simple way to solve this:
Let A be of 4 kg and B be of 3 kg.
And, in A, first element is 5/8th of total and second element if 3/8th of total.
And in B, first element is 1/3rd of total and second element if 2/3rd of total.
Now, if we mix A and B,
First element = (5/8)*4 + (1/3)*3 = 7/2
Second element = (3/8)*4 + (2/3)*3 = 7/2
Thus, ratio of the 2 elements is 7/2 : 7/2 ie 1:1
Let A be of 4 kg and B be of 3 kg.
And, in A, first element is 5/8th of total and second element if 3/8th of total.
And in B, first element is 1/3rd of total and second element if 2/3rd of total.
Now, if we mix A and B,
First element = (5/8)*4 + (1/3)*3 = 7/2
Second element = (3/8)*4 + (2/3)*3 = 7/2
Thus, ratio of the 2 elements is 7/2 : 7/2 ie 1:1
25 Jun 2017, 11:44
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Let E1 and E2 be elements one and two, respectively.
E1 (A) = 5
E2 (A) = 3
Total (A) = 8
E1 (B) = 1
E2 (B) = 2
Total (B) = 3
A in X = 4, which is half of Total (A) - so E1 and E2 in X from A are half of what they are in A.
B in X = 3, which is the same as in Total (B) - so E1 and E2 in X from B are the same as what they are in B.
E1 (X from A) = 5/2
E2 (X from A) = 3/2
E1 (X from B) = 1
E2 (X from B) = 2
[E1 (X from A) + E1 (X from B)] : [E2 (X from A) + E2 (X from B)] = 5/2 + 1 : 3/2 + 2 = 3.5 : 3.5 = 1 : 1. Ans - A.
E1 (A) = 5
E2 (A) = 3
Total (A) = 8
E1 (B) = 1
E2 (B) = 2
Total (B) = 3
A in X = 4, which is half of Total (A) - so E1 and E2 in X from A are half of what they are in A.
B in X = 3, which is the same as in Total (B) - so E1 and E2 in X from B are the same as what they are in B.
E1 (X from A) = 5/2
E2 (X from A) = 3/2
E1 (X from B) = 1
E2 (X from B) = 2
[E1 (X from A) + E1 (X from B)] : [E2 (X from A) + E2 (X from B)] = 5/2 + 1 : 3/2 + 2 = 3.5 : 3.5 = 1 : 1. Ans - A.
06 Sep 2017, 09:27
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farukqmul
Element 1's proportion to the total of each liquid:
A -> 5/8
B -> 1/3
You want alloy X to be formed with 4/7 of it coming from liquid A and 3/7 coming from liquid B, hence:
5/8 * 4/7 + 2/3 * 3/7 = x (...) -> x = 7/14 which is 1/2. For element 1.
The proportion of element 2 coming from each liquids will be the same, and obviously the ratio will also be 1/2. Thus, answer A is the right one.
