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Thelegend2631
Posts: 371
Updated on: 23 Jul 2021, 04:58
Originally posted by Thelegend2631 on 30 Jun 2021, 03:09.
Last edited by Thelegend2631 on 23 Jul 2021, 04:58, edited 5 times in total.
Last edited by Thelegend2631 on 23 Jul 2021, 04:58, edited 5 times in total.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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32% (01:54) correct
68%
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Two cats running towards each other meet after \(t\) \( \) Seconds.
What's the Value of \(t\) in seconds, if it's known that one of the Cat runs at 6m/sec
1. The length of bridge is 100m and the speeds of the cat are in ratio \(2:3\)
2. After they meet, the time taken by the cats to reach the other ends of bridge are \(15\) seconds and \(20/3\) seconds.
Posted from my mobile device
What's the Value of \(t\) in seconds, if it's known that one of the Cat runs at 6m/sec
1. The length of bridge is 100m and the speeds of the cat are in ratio \(2:3\)
2. After they meet, the time taken by the cats to reach the other ends of bridge are \(15\) seconds and \(20/3\) seconds.
Posted from my mobile device
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30 Jun 2021, 04:40
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Two cats running towards each other meet after t \( \) minutes seconds.
What's the Value of t in second, if it's known that one of the Cat runs at 6m/sec.
1. The length of bridge is 100m and the speeds of the cat are in ratio \(2:3\)
If the speeds are 2x and 3x, the time taken to cover the distance will be \(\frac{100}{2x+3x}\) or \(\frac{20}{x}\)
2x=6 or x=3 will give time 20/3
3x=6 or x=2 will give time 20/2 or 10 seconds.
Insufficient
2. After they meet, the time taken by the cats to reach the other ends of bridge are \(15\) seconds and \(20/3\) seconds respectively.
As both meet after t seconds, the time one takes after meeting is for the same distance that the other takes for t seconds before meeting.
What one of the cat, say A, covers in 15 seconds, the other, say B, covers in t seconds. So Ratio of speed A:B=t:15
What A covers in t seconds, the other covers in 20/3 seconds. So Ratio of speed A:B=20/3:t
Thus \(t:15=\frac{20}{3}:t\)
\(\frac{20}{3}*15=t*t…….100=t^2……t=10\)
B
What's the Value of t in second, if it's known that one of the Cat runs at 6m/sec.
1. The length of bridge is 100m and the speeds of the cat are in ratio \(2:3\)
If the speeds are 2x and 3x, the time taken to cover the distance will be \(\frac{100}{2x+3x}\) or \(\frac{20}{x}\)
2x=6 or x=3 will give time 20/3
3x=6 or x=2 will give time 20/2 or 10 seconds.
Insufficient
2. After they meet, the time taken by the cats to reach the other ends of bridge are \(15\) seconds and \(20/3\) seconds respectively.
As both meet after t seconds, the time one takes after meeting is for the same distance that the other takes for t seconds before meeting.
What one of the cat, say A, covers in 15 seconds, the other, say B, covers in t seconds. So Ratio of speed A:B=t:15
What A covers in t seconds, the other covers in 20/3 seconds. So Ratio of speed A:B=20/3:t
Thus \(t:15=\frac{20}{3}:t\)
\(\frac{20}{3}*15=t*t…….100=t^2……t=10\)
B
22 Jul 2021, 01:24
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Is this question properly phrased? From statement 2, how do we know which cat took 15 seconds to reach the other end? Was it the one with 6m/s or the other one?
It seems the author thinks that the use of the word 'respectively' in Statement 2 implies it is the cat with speed 6m/s. But I think this usage leaves a strong room for ambiguity.
If you assume it was the second cat that took 15 seconds, then u get a different answer.
It seems the author thinks that the use of the word 'respectively' in Statement 2 implies it is the cat with speed 6m/s. But I think this usage leaves a strong room for ambiguity.
If you assume it was the second cat that took 15 seconds, then u get a different answer.
. Sorry if it makes the post lengthy) 
