RajatGMAT777
rapidash
As both A and B start at the same time from the same place, the speed gives the distance travelled in 3 minutes.
That is, in 3 mins, A travelled 2 x Distance travelled by B.
As they meet in 3 mins, it would be at the starting point. Therefore, in 3 mins A travelled = 2x800m = 1600m and B travelled 800m.
Now, speed of A = 1600 metres/3mins.
Therefore time taken for 7200metres = 7200 x 3/1600 = 13.5 minutes. (Answer C)
rapidash Bunuel KarishmaBCan you help me explain
That is, in 3 mins, A travelled 2 x Distance travelled by B. which is correctly said as Speed Relation but this x could be any multiple so why are we considering only one lap i.e. 800, can also be 1600 and 3200?
Also, why do we say when A and B meet for the first time in circular loops, the faster one has covered 1 lap more than the slower.
Thank you for your help
I agree with you. The above reasoning doesnt work on all cases.
Its much easier to use plane logic when numbers are so friendly.
I assumed, since Speed of A is double of B, distance covered by A would also be double of B in a given time.
So if A coveres 800m, B would cover 400m.
When A covers 1600m, B would have covered 800m, which is coincidently the start of the lap.
If you want a formula for it, know that A will only meet B after completing initial 800m.
The distance covered by A after completing a lap should match distance covered by B.
So you could also write,
(800+x) = 2x where x is the diance covered by B in 3mins.
That lands you the value of x veing 800m.
The above formula holds true for all relation of A&B, you will only replace (2) with the appropriate factor.
So for speed of A being 3 times of B, the equation would be
(800+x) = 3x
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