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Two squares each with sides of length s are joined to form a rectangle

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Bunuel
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Two squares each with sides of length s are joined to form a rectangle [#permalink] New post   Updated on: 05 Jul 2019, 05:14
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Two squares each with sides of length s are joined to form a rectangle. The area of the rectangle is

(A) s^2
(B) 2s^2
(C) 4s^2
(D) 8s^2
(E) 16s^2

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B

Originally posted by Bunuel on 21 Jun 2017, 00:46.
Last edited by Sajjad1994 on 05 Jul 2019, 05:14, edited 2 times in total.
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Re: Two squares each with sides of length s are joined to form a rectangle [#permalink] New post   21 Jun 2017, 00:55
Bunuel wrote:
Two squares each with sides of length s are joined to form a rectangle. The area of the rectangle is

(A) s^2
(B) 2s^2
(C) 4s^2
(D) 8s^2
(E) 16s^2


Given Two squares each with sides of length \(s\) are joined to form a rectangle.

Side of square \(= s\)

Area of square \(= s^2\)

2 squares forming rectangle will have area \(= s^2 + s^2 = 2s^2 .\) Answer (B) ...
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Re: Two squares each with sides of length s are joined to form a rectangle [#permalink] New post   21 Jun 2017, 00:57
HI,

Let the length of the square be s. When two squares are joined the length would be 2s and breadth is s.

Area of rectangle is 2s*s=2s^2
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Re: Two squares each with sides of length s are joined to form a rectangle [#permalink] New post   21 Jun 2017, 01:28
We have 2 squares with a length s and breadth s.
When kept next to each other, we have a triangle with a length 2s and breadth s
The area of such a rectangle is 2s * s(length * breadth) = 2s^2 (Option B)

Method 2(Assuming numbers)
We can assume value for the length of square(s) : 5cm.
Hence the length of the rectangle is 10cm and breadth is 5cm.
The area is 50cm, which is 2*s^2 = 2*5^2 = 2*25 - 50
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Re: Two squares each with sides of length s are joined to form a rectangle [#permalink]
21 Jun 2017, 01:28
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