Two years ago, Arthur gave each of his five children 20 perc

Question

Two years ago, Arthur gave each of his five children 20 percent of his fortune to invest in any way they saw Fit. In the first year, three of the children, Alice, Bob, and Carol, each earned a profit of 50 percent on their Investments, while two of the children, Dave and Errol, lost 40 percent on their investments. In the second Year, Alice and Bob each earned a 10 percent profit, Carol lost 60 percent, Dave earned 25 percent in profit, And Errol lost all the money he had remaining. What percentage of Arthur's fortune currently remains?

A. 93%
B. 97%
C. 100%
D. 107%
E. 120%

A. 93%
B. 97%
C. 100%
D. 107%
E. 120%

Bunuel · Accepted Answer

Say Arthur's fortune was $100. Then:

A = 20*1.5*1.1 = 33
B = 20*1.5*1.1 = 33
C = 20*1.5*0.4 = 12
D = 20*0.6*1.25 = 15
E = 0

Total 33 + 33 + 12 + 15 = 93.

Answer: A.

doe007 · Answer

Same question: is-there-a-faster-way-to-do-this-fdp-90250.html

jlgdr · Answer

I think Bunuel's approach is fast enough. Anyways, one could use 100 as the total and then play with the numbers, its not that hard. Hope it helps Cheers! J

vad3tha · Answer

Reading and solving the problem took me more than 2 minutes. I hate that time-consuming question!!! :evil:

Nunuboy1994 · Answer

Simple -x as Artuhur's investment divided by 5 - let x be 2000

2000/5= 400

400(1.5) = 600 (3)

400(.60) = 240 (2)

Second Year

600(1.1) = 660 (2)
600(.40) = 240
240 (1.25) = 300

660(2) + 240 + 300 = 1860/2000

186/200 =93/100

Thus
"A"

TimeTraveller · Answer

Percent fortune received by each of A, B, C, D, E = 20%.

Value of the fortune after the first year:
A - 30
B - 30
C - 30
D - 12
E - 12

Value of the fortune after the second year:
A - 33
B - 33
C - 12
D - 15
E - 0

If we assume the initial fortune to be $100, what's left would be $33 + $33 + $12 + $15 = $93 = 93%. Ans - A.

Wonderwoman31 · Answer

I took around 3 minutes to solve this question. Though this question is quite easy, but is there any way that I can save some time

rishab0507 · Answer

Let each get 100 in first year : 
Total asset : 500 
At end of first year 
A : 150 , B: 150, C : 150
D : 60, E : 60

At end of 2nd year 
A: 165 , B: 165, C : 60, D : 75 ,E : 0
Total : 165+165+60+75 =465
% lost : 465/500 *100 : 93

IMO :A

ScottTargetTestPrep · Answer

Solution:
 
We can let Arthur’s total fortune be $100. Thus, each child received $20. Now, let’s determine the amount of money each child has after 2 years.

Alice: 20 x 1.5 x 1.1 = $33

Bob: $33 (since his numbers are identical to those of Alice)

Carol: 20 x 1.5 x 0.4 = $12

Dave: 20 x 0.6 x 1.25 = $15

Errol: $0 (since he lost all of his money)

Therefore, the total they have after 2 years is 33 + 33 + 12 + 15 + 0 = $93, which is 93% of $100.

Answer: A

Adarsh_24 · Answer

Another method:

Using successive increase/decrease formula.
Cumulative change of A = 50+10+(50*10)/100 = 65%
B=same as A = 65%
C=50-60-(3000/100)=-40%
D=-40+25-(1000/100)=-25%
E Dont care as lost all money

Cumulative sum of all = x/5 (165+165+60+75) = 465x/5 = 93x
% of total = 93x/x *100 =93

bumpbot · Answer

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Two years ago, Arthur gave each of his five children 20 perc

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