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Re: Trouble with Quant? Some tips/traps that might help you...
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25 Jul 2010, 04:54
Thanks a lot. Very useful post. I am in a way of compiling such strategies. Will post it soon
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Re: Trouble with Quant? Some tips/traps that might help you...
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25 Jul 2010, 05:14
RenukaD wrote: Thanks a lot. Very useful post. I am in a way of compiling such strategies. Will post it soon We are awaiting more strategies. thanks
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Re: Trouble with Quant? Some tips/traps that might help you...
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26 Jul 2010, 04:45
an excellent post!



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03 Aug 2010, 20:32
great article for the gmat club weekly newsletter! thank you!



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Re: Trouble with Quant? Some tips/traps that might help you...
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20 Aug 2010, 00:03
this what i call an excellent job ! Thanks a lot



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Re: Trouble with Quant? Some tips/traps that might help you...
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20 Aug 2010, 09:21
This post is on my final test test checklist to look over, headed to the center now.. Thanks again!



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03 Oct 2010, 01:03
Rubyswtgrl wrote: Is the answer for Lucky Twin question D? I first thought it was E, thinking that 6^anything would be an even number, hence 678,463 would not be a multiple of an even number. But I googled the answer and since the question lists set S as the first 10 nonnegative integers, set S *includes* 0 (sneaky question, I was thinking 1, 2, 3, etc.). So since 0 has a 10% chance of being selected, K could = 0, making Z equal to 1, and 678,463 is a multiple of 1. So D = 90% is the correct answer. I guess Lucky Twin worked here , but my first choice still would have been the above.
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GMATT73 wrote: You can add in "Lucky Twins" to your repertoire
The purpose of this problem is to exploit a weakness used by PVue: complimentary answer choices. Almost always in complimentary probability questions, there are a pair of "LUCKY TWINS" among the answer choices. If in doubt and pressed for time, choose a TWIN by logical deduction.
Let`s take a crack at this Project GMAT bad boy without making lengthy calculations.
Set S consists of numbers 2, 3, 6, 48, and 164. Number K is computed by multiplying one random number from set S by one of the first 10 nonnegative integers, also selected at random. If Z=6^K, what is the probability that 678,463 is not a multiple of Z?
a. 10% b. 25% c. 50% d. 90% e. 100%
*LUCKY TWINS I don't understand what you mean by "lucky twins". How does that work?



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Re: Trouble with Quant? Some tips/traps that might help you...
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22 Oct 2010, 11:46
very helpful indeed!
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MateoLibre wrote: GMATT73 wrote: You can add in "Lucky Twins" to your repertoire
The purpose of this problem is to exploit a weakness used by PVue: complimentary answer choices. Almost always in complimentary probability questions, there are a pair of "LUCKY TWINS" among the answer choices. If in doubt and pressed for time, choose a TWIN by logical deduction.
Let`s take a crack at this Project GMAT bad boy without making lengthy calculations.
Set S consists of numbers 2, 3, 6, 48, and 164. Number K is computed by multiplying one random number from set S by one of the first 10 nonnegative integers, also selected at random. If Z=6^K, what is the probability that 678,463 is not a multiple of Z?
a. 10% b. 25% c. 50% d. 90% e. 100%
*LUCKY TWINS I don't understand what you mean by "lucky twins". How does that work? Detailed answer: Total universe of possibilities for K: [a # from set S]*[0,1,2,..9] = [2*0 = 0, 2*1 = 2, .. 2*9=.... 3*0= 0, 3*1= 3...168*0, 168*1... 168*9] = total of 50 possible values of k. Out of that we'd have 5 0's. Probability of k being 0 = 5/50 = 1/10. Also, as mentioned in one of the previous posts, 6^0 =1 and 678 or 463 are multiples of 1. So there is a 10% chance that the numbers 678, 463 will be a factor of 6^k. So ans = 10010 = 90 or d. Now using the 'logic' of Lucky Twins  10 and 90 are the only options out of the 5 that are complementary (10=10090). None of the other options have their complements as options. So by the theory of Lucky Twins we can deduce that the answer is most probably either a or d. Also, since the units digit of 6^k will always be 6 as long as k != 0, the probability of 6^k NOT being a multiple of 678 or 463 should be pretty high. So the answer must be d or 90% and not 10%.



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Re: Trouble with Quant? Some tips/traps that might help you...
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11 Jan 2011, 13:43
thanks. great post



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Re: Trouble with Quant? Some tips/traps that might help you...
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11 Feb 2011, 00:01
Ill read it again the night before my exam.thx : )



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Re: Trouble with Quant? Some tips/traps that might help you...
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08 Apr 2011, 01:09
First, let me congratulate necromonger for the enormous amount of detail shared. I think the original post is simply outstanding. I'd also want to add two specific traps that I've frequently encountered: 1. In questions where Diameter and radius are involved, watch out carefully for what exactly the answer and the question deal in and ensure that the translation of the values between radius and diameter are done at every stage of the solution. 2. One often assumes integer values even if the question is not explicit about the nature of the numbers involved. I did this and have got some practise questions wrong 3. Venndiagram questions and Algebra questions often appear very similar. I will add more later to this list.
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27 Aug 2011, 15:06
The lone wolf  GREAT TIP!!



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Re: Trouble with Quant? Some tips/traps that might help you...
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29 Aug 2011, 17:07
Can somebody please explain me the lone wolf problem with the solution.
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Re: Trouble with Quant? Some tips/traps that might help you...
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02 Sep 2011, 01:16
Brilliant post! Many thanks!
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Re: Trouble with Quant? Some tips/traps that might help you...
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02 Sep 2011, 03:01
maheshsrini wrote: Can somebody please explain me the lone wolf problem with the solution. Here you go: On a loan, evil necromonger charges X% interest in the first year, and Y% interest in the second. If he loaned Rhyme 20,000$ in 2006, how much Rhyme pay by interest in 2008?" A) X = 10 B) (X + Y + XY/100) = 100 The intent of the question was to say the following: On a deposit of $20,000, interest is paid at a rate of X% in the first year and at Y% in the second year. What is the total interest paid by the end of second year if no money was withdrawn? On 20,000, you pay X% interest in the first year. Interest paid in first year = (X/100) * 20,000 Next year, you pay Y% interest on the total amount. Interest paid in the second year = (Y/100) * [20,000 + (X/100) * 20,000] = (Y/100)*20,000 + (XY/10,000)*20,000 Total interest paid in the two years = (X/100) * 20,000 + (Y/100)*20,000 + (XY/10,000)*20,000 = 200 * (X + Y + XY/100) All you need to answer the question is the value of '(X + Y + XY/100)' which statement 2 gives you.
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Re: Trouble with Quant? Some tips/traps that might help you...
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14 Jan 2012, 23:41
Fun and super useful post.. As you put it I am set to dig my grave by spenidng too much of time.. Bless my soul



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Re: Trouble with Quant? Some tips/traps that might help you...
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16 Jan 2012, 10:05
Printed out as a reference, appreciate it!



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Re: Trouble with Quant? Some tips/traps that might help you...
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11 Feb 2012, 17:53
More good material, thanks for these tips.




Re: Trouble with Quant? Some tips/traps that might help you... &nbs
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