x^5>x^4
x^4.(x-1)>0
---->x^4 is certainly positive or a zero, then x-1>0 ----> x>1. Thus, the question actually ask whether x>1 or not
1) x^3>−x
x.(x^2+1)>0
--> (x^2+1) is definitely positive, then x>0
--> we were asked whether or not x>1. We only know from Statement (1) that x>0. This can either satisfy x>1 (i.e. x=2) or cannot satisfy x>1 (i.e. x=0.5)
NOT SUFFICIENT.
(2) 1/x-x<0
(1-x^2)/x<0
(1-x)(1+x)/x<0
--> The solution for the above inequality is -1<x<0 or x>1.
--> Again, we were asked whether or not x>1. We only know from statement (2) that -1<x<0 or x>1. This can either satisfy x>1 (i.e. x=2 or x>1) or cannot (i.e. x=-0.5 or -1<x<0)
NOT SUFFICIENT.
Combining both (1) and (2):
Intersecting the two following solutions:
1) x>0
2) -1<x<0 or x>1,
we obtain that x>1. This exactly addresses what is asked by the question (whether x>1 or not).
SUFFICIENT
Answer is (C)
Smack that +1 kudo if you like my explanation