November 20, 2018 November 20, 2018 09:00 AM PST 10:00 AM PST The reward for signing up with the registration form and attending the chat is: 6 free examPAL quizzes to practice your new skills after the chat. November 20, 2018 November 20, 2018 06:00 PM EST 07:00 PM EST What people who reach the high 700's do differently? We're going to share insights, tips and strategies from data we collected on over 50,000 students who used examPAL.
Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 03 Jul 2013
Posts: 89

Is x^5 > x^4?
[#permalink]
Show Tags
Updated on: 05 Oct 2014, 07:51
Question Stats:
45% (02:15) correct 55% (02:06) wrong based on 413 sessions
HideShow timer Statistics
Is x^5 > x^4? (1) x^3 > −x (2) 1/x < x
Official Answer and Stats are available only to registered users. Register/ Login.
_________________
Sometimes standing still can be, the best move you ever make......
Originally posted by aadikamagic on 05 Oct 2014, 07:12.
Last edited by Bunuel on 05 Oct 2014, 07:51, edited 1 time in total.
Edited the question.




Math Expert
Joined: 02 Sep 2009
Posts: 50627

Re: Is x^5 > x^4?
[#permalink]
Show Tags
05 Oct 2014, 08:00




Manager
Joined: 03 Jul 2013
Posts: 89

Re: Is x^5 > x^4?
[#permalink]
Show Tags
05 Oct 2014, 09:07
Thanks Bunuel. The take away for me here is that we can always divide by squares without bothering about sign changes.
_________________
Sometimes standing still can be, the best move you ever make......



Intern
Joined: 06 Nov 2013
Posts: 25

Re: Is x^5 > x^4?
[#permalink]
Show Tags
06 Oct 2014, 01:29
Bunuel, can you please explain this :"x < x^3 > x(x^2 1) > 0 > (x + 1)x(x  1) > 0 > 1 < x < 0 or x > 1. Not sufficient." " i understand that " (x + 1)x(x  1) > 0" and then the three roots are = 1,1,0. Since the inequality is ">", x is " outside these values. But how did we come to "1 < x < 0 or x > 1." I came to : x(x+1)(x1)>0 either x>0 or (x+1)(x1)>0 and then im lost. Please Help
_________________
'I read somewhere... how important it is in life not necessarily to be strong, but to feel strong... to measure yourself at least once.'



Math Expert
Joined: 02 Sep 2009
Posts: 50627

Re: Is x^5 > x^4?
[#permalink]
Show Tags
06 Oct 2014, 01:55
shreyagmat wrote: Bunuel, can you please explain this :"x < x^3 > x(x^2 1) > 0 > (x + 1)x(x  1) > 0 > 1 < x < 0 or x > 1. Not sufficient."
" i understand that " (x + 1)x(x  1) > 0" and then the three roots are = 1,1,0. Since the inequality is ">", x is " outside these values. But how did we come to "1 < x < 0 or x > 1."
I came to : x(x+1)(x1)>0 either x>0 or (x+1)(x1)>0
and then im lost. Please Help (x + 1)x(x  1) > 0 > the "roots", in ascending order, are 1, 0 and 1, this gives us 4 ranges: x < 1; 1 < x < 0; 0 < x < 1; x > 1. Next, test some extreme value for x: if x is some large enough number, say 10, then all three multiples will be positive which gives the positive result for the whole expression, so when x>1, the expression is positive. Now the trick: as in the 4th range expression is positive, then in the 3rd it'll be negative, in the 2nd it'll be positive and finally in the 1st it'll be negative:  +  + . So, the ranges when the expression is positive are: 1 < x < 0 and x > 1. Theory on Inequalities: Solving Quadratic Inequalities  Graphic Approach: solvingquadraticinequalitiesgraphicapproach170528.htmlInequality tips: tipsandhintsforspecificquanttopicswithexamples172096.html#p1379270inequalitiestrick91482.htmldatasuffinequalities109078.htmlrangeforvariablexinagiveninequality109468.htmleverythingislessthanzero108884.htmlgraphicapproachtoproblemswithinequalities68037.htmlAll DS Inequalities Problems to practice: search.php?search_id=tag&tag_id=184All PS Inequalities Problems to practice: search.php?search_id=tag&tag_id=189700+ Inequalities problems: inequalityandabsolutevaluequestionsfrommycollection86939.htmlHope this helps.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



Intern
Joined: 06 Nov 2013
Posts: 25

Re: Is x^5 > x^4?
[#permalink]
Show Tags
06 Oct 2014, 03:44
Thank you Bunuel. That was very quick. I think I got it now.
_________________
'I read somewhere... how important it is in life not necessarily to be strong, but to feel strong... to measure yourself at least once.'



Manager
Joined: 04 Oct 2013
Posts: 171
Concentration: Finance, Leadership
GMAT 1: 590 Q40 V30 GMAT 2: 730 Q49 V40
WE: Project Management (Entertainment and Sports)

Re: Is x^5 > x^4?
[#permalink]
Show Tags
07 Oct 2014, 03:54
aadikamagic wrote: Is x^5 > x^4?
(1) x^3 > −x (2) 1/x < x It can also quickly be solved thinking about ranges. Is \( x^5 > x^4 \)? If you think about it, the question is implicitly asking whether a value is greater than one. Indeed every other option (numbers smaller than 1; numbers between 1 and 0; numbers between 0 and 1) if plugged into the expression results in a false statement. 1) picking numbers you can figure out that: I. the inequality is satisfied when our value is greater than zero. ( pick 1/3. (1/3)^3 is never gonna be greater than [(1/3)]. Same reasoning holds for numbers <= than 1) II. the inequality is satisfied for both proper fractions and values greater than 1. NS 2) plugging in numbers you can figure out that the inequality is satisfied for values between both 1 and 0 and greater than 1. NS 1+2) First statement rules out any value smaller than zero. second statement rules out any proper fraction. Our overlapping result is going to be a value grater than one, making us able to claim an answer. C. Hope it helps gmat6nplus1.
_________________
learn the rules of the game, then play better than anyone else.



Manager
Joined: 22 Jan 2014
Posts: 176
WE: Project Management (Computer Hardware)

Re: Is x^5 > x^4?
[#permalink]
Show Tags
07 Oct 2014, 09:31
Bunuel wrote: Is x^5 > x^4?
Is \(x^5 > x^4\)? > reduce by x^4: is \(x > 1\)?
(1) x^3 > −x > \(x(x^2 + 1) > 0\). Since \(x^2 + 1\) is always positive, then the second multiple, x, must also be positive. So, this statement implies that x > 0. Not sufficient.
(2) 1/x < x > multiply by x^2 (it has to be positive, so we can safely do that): \(x < x^3\) > \(x(x^2 1) > 0\) > \((x + 1)x(x  1) > 0\) > \(1 < x < 0\) or \(x > 1\). Not sufficient.
(1)+(2) Intersection of ranges from (1) and (2) is \(x > 1\). Sufficient.
Answer: C. Hi Bunuel I was able to solve the ques by plugging in values but can you explain how did x < x^3 become x(x^21) > 0 how did you know x^3 would be a negative quantity and took it LHS and change the inequality sign? Please explain.
_________________
Illegitimi non carborundum.



Director
Joined: 25 Apr 2012
Posts: 689
Location: India
GPA: 3.21
WE: Business Development (Other)

Re: Is x^5 > x^4?
[#permalink]
Show Tags
07 Oct 2014, 09:41
aadikamagic wrote: Is x^5 > x^4?
(1) x^3 > −x (2) 1/x < x The given question can be rewritten as as \(x^{5}x^{4} >0\)> \(x^{4}*(x1)>0\) Now we know that \(x^{4}\geq{0}\) so we need to know whether x=0 or \(x\neq{0}\) St 1 says \(x^{3}+x>0\) or \(x(x^2+1)>0\)...If this true we can safely say that \(x\neq{0}\) and \(x>0\) Now if x=2 the above expression \(x^{4}*(x1)>0\) is true but if x=1/2 then \(x^{4}*(x1)>0\) is false Option A and D ruled out St 2 says 1/x < x or \(\frac{(x^21)}{x} >0\) Now this expression is true when Numerator and Denominator are of same sign.. Case 1: When N and D are positive so we have x>0 and\(x^{2}\) > 1 or x>1 or x>1 or x<1 but we know x>0 so we have x>1..For x>1 the expression is always positive Case 2: When N and D are of negative sign so we have x<0 and\(x^{2}<1\) or x<1 or 1<x<1...but if we know x<0 so we have x in the range 1<x<0.. So if x=1/2 the expression \(x^{4}*(x1)>0\) is false Thus from St2 also we have 2 answers possible.. Combining both statements we get that x>1 and the expression \(x^{4}*(x1)>0\) is true for all values x>1 Ans C
_________________
“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”



Math Expert
Joined: 02 Sep 2009
Posts: 50627

Re: Is x^5 > x^4?
[#permalink]
Show Tags
08 Oct 2014, 00:32
thefibonacci wrote: Bunuel wrote: Is x^5 > x^4?
Is \(x^5 > x^4\)? > reduce by x^4: is \(x > 1\)?
(1) x^3 > −x > \(x(x^2 + 1) > 0\). Since \(x^2 + 1\) is always positive, then the second multiple, x, must also be positive. So, this statement implies that x > 0. Not sufficient.
(2) 1/x < x > multiply by x^2 (it has to be positive, so we can safely do that): \(x < x^3\) > \(x(x^2 1) > 0\) > \((x + 1)x(x  1) > 0\) > \(1 < x < 0\) or \(x > 1\). Not sufficient.
(1)+(2) Intersection of ranges from (1) and (2) is \(x > 1\). Sufficient.
Answer: C. Hi Bunuel I was able to solve the ques by plugging in values but can you explain how did x < x^3 become x(x^21) > 0 how did you know x^3 would be a negative quantity and took it LHS and change the inequality sign? Please explain. x < x^3 0 < x^3  x 0 < x(x^2  1), which is the same as x(x^2  1) > 0 .
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



CEO
Joined: 20 Mar 2014
Posts: 2635
Concentration: Finance, Strategy
GPA: 3.7
WE: Engineering (Aerospace and Defense)

Re: Is x^5 > x^4? (1) x^3 > −x (2) 1/x < x
[#permalink]
Show Tags
08 Jan 2016, 10:06
shasadou wrote: Is x^5 > x^4?
(1) x^3 > −x (2) \(\frac{1}{x}\) < x You are asked is \(x^5 > x^4\) > \(x^5x^4>0\)> \(x^4(x1) > 0\) > as \(x^4 > 0\) for all x > the question basically asks us whether x>1 ? Per statement 1,\(x^3 > −x\) > \(x^3 + x> 0\) > x(x^2+1)>0 > x>0 (as \(x^2+1 > 0\) for all x) but is x>1 ? no definite answer. Not sufficient. Per statement 2, 1/x < x > 1/x  x<0 > (1x^2)/x < 0 > (x^21)/x > 0 > (x+1)(x1)/x > 0 > 1<x<0 or x>1 , again not sufficient to give you a definite answer. Combining the 2 statements you get, x>1, thus giving a definite yes to the question asked. C is thus the correct answer. Hope this helps.



Math Revolution GMAT Instructor
Joined: 16 Aug 2015
Posts: 6523
GPA: 3.82

Re: Is x^5 > x^4?
[#permalink]
Show Tags
10 Jan 2016, 17:49
Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution. Is x^5 > x^4? (1) x^3 > −x (2) 1x < x When it comes to an inequality, when a range of 1) square and 2) que includes a range of con, the con is sufficient. These two facts are important. When you modify the original condition and the question, it becomes x^5x^4>0?, x^4(x1)>0?, x1>0?, x>1?.(As x^4 is a positive number, the direction of the sign is not changed when the both equations are divided.) There is 1 variable(x), which should match with the number of equations. So you need 1 equation. For 1) 1 equation, for 2) 1 equation, which is likely to make D the answer. For 1), x^2+1>0 is always valid from x^3+x>0, x(x^2+1)>0, which makes x>0. Since the range of que doesn’t contain the range of con, it is not sufficient. For 2), 1<x<0, 1<x is derived from x<x^3(the direction of the sign doesn’t change when x^2 is multiplied to the both equations. When it comes to an inequality, square only matters.), 0<x^3x, 0<x(x^21), 0<x(x1)(x+1). Since the range of que doesn’t contain the range of con, it is not sufficient. When 1) & 2), from x>1, the range of que contains the range of con, which is sufficient. Therefore the answer is C. For cases where we need 1 more equation, such as original conditions with “1 variable”, or “2 variables and 1 equation”, or “3 variables and 2 equations”, we have 1 equation each in both 1) and 2). Therefore, there is 59 % chance that D is the answer, while A or B has 38% chance and C or E has 3% chance. Since D is most likely to be the answer using 1) and 2) separately according to DS definition. Obviously there may be cases where the answer is A, B, C or E.
_________________
MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The oneandonly World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only $99 for 3 month Online Course" "Free Resources30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons  try it yourself"



VP
Joined: 05 Mar 2015
Posts: 1000

Is x^5>x^4?
[#permalink]
Show Tags
28 Sep 2016, 09:08
Keats wrote: Is x^5>x^4?
1. x^3 > x 2. 1/x < x rewording the question as is x>1 (cancel x^4 both sides) ?? 1. x(x^2+1)>0 means x>0 if x=2 .....yes if x=0.5 ....No.......Insuff.... 2. 1/xx<0 (1x)(1+x)/x<0 breakpoints are 1,0,1 thus x is in range 1<x<0 && x>1 satisfies the condition let x=2......Yes x=0.5 ....No.........insufff... combining both we know from 1 x>0 and from 2 that x>1 thus we have definite ans x>1.......suff.. Ans C



Manager
Joined: 24 Aug 2016
Posts: 68
Location: India
WE: Information Technology (Computer Software)

Re: Is x^5 > x^4?
[#permalink]
Show Tags
04 Oct 2016, 21:36
\(x^5 > x^4\) ==> \(x^5  x^4 > 0\) ==> \(x^4 (x  1) > 0\) ==> x 1 > 0 ( As \(x^4\) will always be positive.) ==> x > 1 ? (1) \(x^3 > x\) ==> \(x^2(x+1)>0\) ==> x > 1  Not sufficient. (2) \(\frac{1}{x}\)< x ==> \(x^2 > 1\) ==> x> 1 or x < 1  Not sufficient. When we combine (1) and (2), x can't be < 1. So, X > 1 Ans C.
_________________
"If we hit that bullseye, the rest of the dominos will fall like a house of cards. Checkmate."



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8550
Location: Pune, India

Re: Is x^5 > x^4?
[#permalink]
Show Tags
13 Jul 2017, 23:29
aadikamagic wrote: Is x^5 > x^4?
(1) x^3 > −x (2) 1/x < x Responding to a pm: All the given information can be manipulated to form factors. I have discussed how to deal with multiple factors in these posts: https://www.veritasprep.com/blog/2012/0 ... efactors/https://www.veritasprep.com/blog/2012/0 ... nsparti/https://www.veritasprep.com/blog/2012/0 ... spartii/Is x^5 > x^4? Is x^5  x^4 > 0? Is x^4(x  1) > 0? We ignore the even powers because x^4 will never be negative. But we need to ensure that x should not be 0 for the inequality to hold. Is (x  1) > 0? Is x > 1? Statement 1: x^3 > −x x^3 + x > 0 x(x^2 + 1) > 0 x^2 + 1 will always be positive. So we see that x > 0. But we need to know whether it is greater than 1. Greater than 0 could be 0.5 or it could be 2 (or any other number). So this is not sufficient to say whether x will eb greater than 1. Not sufficient. (2) 1/x < x When the sign of x is not known, we do not multiply by x. We bring it to the o there side. (1/x)  x < 0 (1  x^2)/x < 0 (x^2  1)/x > 0 (x + 1)(x  1)/x > 0 The transition points on the number line are 1, 0, and 1. The expression will be positive when x > 1 or 1 < x < 0. This alone is also not sufficient. Both together we know that x is positive and x > 1 or 1 < x < 0. So x > 1 is a must. Sufficient. Answer (C)
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >
GMAT selfstudy has never been more personalized or more fun. Try ORION Free!



BSchool Forum Moderator
Joined: 05 Jul 2017
Posts: 489
Location: India
GPA: 4

Re: Is x^5 > x^4?
[#permalink]
Show Tags
20 Sep 2017, 10:36
Bunuel wrote: Is x^5 > x^4?
Is \(x^5 > x^4\)? > reduce by x^4: is \(x > 1\)?
(1) x^3 > −x > \(x(x^2 + 1) > 0\). Since \(x^2 + 1\) is always positive, then the second multiple, x, must also be positive. So, this statement implies that x > 0. Not sufficient.
(2) 1/x < x > multiply by x^2 (it has to be positive, so we can safely do that): \(x < x^3\) > \(x(x^2 1) > 0\) > \((x + 1)x(x  1) > 0\) > \(1 < x < 0\) or \(x > 1\). Not sufficient.
(1)+(2) Intersection of ranges from (1) and (2) is \(x > 1\). Sufficient.
Answer: C. Hey Bunuel, How can you divide the equation by x^4 throughout ? As we don't know the value of x. We can't do that right? what if x was 0 , then we can't reduce a equation by 0 Please let me know if I am wrong. Eager to hear back from you
_________________
My journey From 410 to 700 Here's my experience when I faced a glitch in my GMAT Exam Don't do this mistake when you give your GMATPrep Mock! NEW GMATPrep software analysis by Bunuel



Math Expert
Joined: 02 Sep 2009
Posts: 50627

Re: Is x^5 > x^4?
[#permalink]
Show Tags
20 Sep 2017, 10:46
pikolo2510 wrote: Bunuel wrote: Is x^5 > x^4?
Is \(x^5 > x^4\)? > reduce by x^4: is \(x > 1\)?
(1) x^3 > −x > \(x(x^2 + 1) > 0\). Since \(x^2 + 1\) is always positive, then the second multiple, x, must also be positive. So, this statement implies that x > 0. Not sufficient.
(2) 1/x < x > multiply by x^2 (it has to be positive, so we can safely do that): \(x < x^3\) > \(x(x^2 1) > 0\) > \((x + 1)x(x  1) > 0\) > \(1 < x < 0\) or \(x > 1\). Not sufficient.
(1)+(2) Intersection of ranges from (1) and (2) is \(x > 1\). Sufficient.
Answer: C. Hey Bunuel, How can you divide the equation by x^4 throughout ? As we don't know the value of x. We can't do that right? what if x was 0 , then we can't reduce a equation by 0 Please let me know if I am wrong. Eager to hear back from you If it were x^5 < x^4, then after dividing by x^4 we'd get x < 1 but x cannot be 0, so it would be x< 0 or 0 < x < 1. x^5 > x^4 gives x > 1, so it's redundant to mention that x cannot be 0 because we got x > 1.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics



SVP
Joined: 26 Mar 2013
Posts: 1882

Re: Is x^5 > x^4?
[#permalink]
Show Tags
21 Sep 2017, 03:46
aadikamagic wrote: Is x^5 > x^4?
(1) x^3 > −x (2) 1/x < x x^5 > x^4 x^5  x^4 > 0 x^4 ( x  1) > 0..........x^4 is always positive........So the question boils down to: Is x > 1?? (Note: you can divide by x^4 because it is positive and hence no sign change) (1) x^3 > −x x^3 + x > 0 x ( x^2 + 1) > 0...........( x^2 + 1) is always positive.......then x cant take any positive number Let x = 1/2........... Answer is No Let x =2 ...............Answer is Yes Insufficient (2) 1/x < x To be safe, test 1/2, 1/2, 2, 2.......... (Note: 2 & 1/2 will yield Invalid results so they are out.) Let x = 1/2.........Answer is No Let x = 2 ............Answer is Yes Insufficient Combine 1 & 2 The intersection happens when x > 1 Sufficient Answer: C



Manager
Joined: 02 Jan 2017
Posts: 76
Location: Pakistan
Concentration: Finance, Technology
GPA: 3.41
WE: Business Development (Accounting)

Is x^5 > x^4?
[#permalink]
Show Tags
27 Dec 2017, 01:40
Bunuel wrote: Is x^5 > x^4?
Is \(x^5 > x^4\)? > reduce by x^4: is \(x > 1\)?
(1) x^3 > −x > \(x(x^2 + 1) > 0\). Since \(x^2 + 1\) is always positive, then the second multiple, x, must also be positive. So, this statement implies that x > 0. Not sufficient.
(2) 1/x < x > multiply by x^2 (it has to be positive, so we can safely do that): \(x < x^3\) > \(x(x^2 1) > 0\) > \((x + 1)x(x  1) > 0\) > \(1 < x < 0\) or \(x > 1\). Not sufficient.
(1)+(2) Intersection of ranges from (1) and (2) is \(x > 1\). Sufficient.
Answer: C. Can we just reduce the equation by \(x^4\), when we do not the sign of the variables? Will that not be wrong? If it is right to reduce by \(x^4\) in this question, how do we assess this for other questions? What do we base our judgment on to divide by variables? Or is you reduced here because \(x^5> x^4\) could only hold if \(x>1\)? Separate from the question above if we manipulated the stem this way would it be right? \(x^5  x^4>0\) \(x^4(x  1)>0\) Therefore either \(x^4>0 > x > 0\) \(Or x >1\) Kindly explain.



Math Expert
Joined: 02 Sep 2009
Posts: 50627

Re: Is x^5 > x^4?
[#permalink]
Show Tags
27 Dec 2017, 02:15
mtk10 wrote: Bunuel wrote: Is x^5 > x^4?
Is \(x^5 > x^4\)? > reduce by x^4: is \(x > 1\)?
(1) x^3 > −x > \(x(x^2 + 1) > 0\). Since \(x^2 + 1\) is always positive, then the second multiple, x, must also be positive. So, this statement implies that x > 0. Not sufficient.
(2) 1/x < x > multiply by x^2 (it has to be positive, so we can safely do that): \(x < x^3\) > \(x(x^2 1) > 0\) > \((x + 1)x(x  1) > 0\) > \(1 < x < 0\) or \(x > 1\). Not sufficient.
(1)+(2) Intersection of ranges from (1) and (2) is \(x > 1\). Sufficient.
Answer: C. Can we just reduce the equation by \(x^4\), when we do not the sign of the variables? Will that not be wrong? If it is right to reduce by \(x^4\) in this question, how do we assess this for other questions? What do we base our judgment on to divide by variables? Or is you reduced here because \(x^5> x^4\) could only hold if \(x>1\)? Separate from the question above if we manipulated the stem this way would it be right? \(x^5  x^4>0\) \(x^4(x  1)>0\) Therefore either \(x^4>0 > x > 0\) \(Or x >1\) Kindly explain. When dividing by negative value we should flip the sign of the inequality, when dividing by positive value we should keep the sign of the inequality. x^4 cannot be negative, so we can divide and write x > 1. If it were x^5 < x^4, then after we divide by x^4, we'd get x < 1 but here we should mention that x ≠ 0 because if x = 0, then x^5 = x^4 = 0.
_________________
New to the Math Forum? Please read this: Ultimate GMAT Quantitative Megathread  All You Need for Quant  PLEASE READ AND FOLLOW: 12 Rules for Posting!!! Resources: GMAT Math Book  Triangles  Polygons  Coordinate Geometry  Factorials  Circles  Number Theory  Remainders; 8. Overlapping Sets  PDF of Math Book; 10. Remainders  GMAT Prep Software Analysis  SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS)  Tricky questions from previous years.
Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
What are GMAT Club Tests? Extrahard Quant Tests with Brilliant Analytics




Re: Is x^5 > x^4? &nbs
[#permalink]
27 Dec 2017, 02:15



Go to page
1 2
Next
[ 24 posts ]



