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for divisibility by 12,check for 3 and 4.
since after dividing remainder is 7,meaning after dividing by 3 remainder = 1
and after dividing by 4 remainder = 3.

so check for 151 giving 1 and 3 respectively.

also for 5995 (sum of the digits = 28) hence dividing by 3 remainder = 1 (3*9=27)
also for 4 (6000 is divisible,similarly 5996 is divisible,hence 5992 is divisible)

thus 5995-5992=3 will be remainder after dividing by 4.

thus C it is.So,without actual dividing you can test like this.
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Thanks Jack for the clear explanation
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normal division looks much simpler ... and wont take much time as well :)
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enigma123
Which of the following would result in a remainder of 7 when divided by 12?

I. 151

II. 3,443

III. 5,995

A) I only

B) I and II

C) I and III

D) II and III

E) I, II and III

How come the answer is C? 5995 Divided by 12 doesn't leave a remainder 7. Any idea people?

the question is asking which will have a remainder 1 when divided by 3?
answer C
less than 15 seconds :-D
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It al comes down to basic in the end,I guess.
x=12q+7
151=12q+7
144=12q
q=12
like wise can be found for other two.
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If a number has a remainder of 7 when divided by 12 it will have a remainder of 1 when divided by 3 --> 1 2 3 4 5 6 7. So all you have to do is divide all numbers by 3.
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sq01
If a number has a remainder of 7 when divided by 12 it will have a remainder of 1 when divided by 3 --> 1 2 3 4 5 6 7. So all you have to do is divide all numbers by 3.

Hi, sq01 and Nez,

It may not be correct idea to check only by 3 and take that as the answer..
You may have got the correct answer but may not be some other day in some other Q..

When 3 leaves a remainder of 1, the number div by 12 can leave a remainder of 1,4,7, or 10..
for example if one of the choice was 121. 121 leaves a remainder of 1 when div by 3, so you would mark tht as he answer.
But that would be wrong, since 121 leaves a remainder of 1, when div by 12..

therefore check for 3 and 4..
3 should leave a remainder 1, and 4 should leave a remainder of 3..
so if the number +1 is div by 4, that is our answer..

121 +1=122 this is not div by 4 as last two digits are not div by 4..
151 +1 = 152, 52 is div by 4, this is one of our answer.

Hope it helps
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only way to solve this question is via long division and see what is the remainder when the numbers are divided by 12
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My technique was the followin:

1. We need to confirm that these numbers have a reminder of 7 when divided by 12:

\(x/12=k+7\)
\(x=12k+7\)

what if we add 5 to each answee and check that the answer is divisible by 12?


\(x+5 = 12k + (7+5) = 12(k+1)\)

I. 151 -> 151+5 = 156 correct:divisible by 4 and by 3
II. 3,443 -> 3448 -> wrong: the sum of the digits is not multiple of 3
III. 5,995 -> 6,000 clearly correct

Best,

Andres
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