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Always remember GMAT never asks for complex calculations .So whenever you see questions like this ,try to identify the pattern .In this case ,the fraction is a recurring decimal 0.027027027... 027 keeps on repeating .18th digit is 3*6 so 7 is the answer

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\(\frac{1}{37}\) could be a difficult or at least if not approched well could lead to the wron answer or prone of error

So, do \(\frac{100}{37}\) in this way is more comfortable and in the end you will add 2 zeros

we want the 18 th number and 18 is even

\(\frac{100}{37}\) \(=\) \(270270\) ------------> \(0.0270270\)

Now notice the first number is 0 second 2 third 7 and the fourth again 0

So \(4 * 4 = 16\) in our pattern.

So is \(ZERO\) \(+ 2 = 7\) ( be carefull we are talking of units place not sum)

D is the answer


hi
how can you say so ...?

.027 027 027

here we can see a set of "027" composed of 3 digits, NOT of 4 digits ...
to find the 18th digit, we can arrange 6 identical sets as shown above. Clearly the 18th digit is 7...

thanks ...
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Time taken 27 secs

Multiply the numerator and the denominator by 27.

so, 1/37= 27/27*37 = 27/999 = 0.027027... (Property of terminating decimal)

Hence, 7
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i also remember the rule that: we put the repeating part on the numerator, the length of repeating part will be the number of 9s in the denomnator
so 027/999 = 27/999 = 0/027027027
but how can we know 27*37 = 999 quickly
rever08
Time taken 27 secs

Multiply the numerator and the denominator by 27.

so, 1/37= 27/27*37 = 27/999 = 0.027027... (Property of terminating decimal)

Hence, 7

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