The weight of a glass of jar is 20% of the weight of the jar

Question

The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?
a.1/5
b.1/3
c.2/5
d.1/2
e.2/3

Somebody to suggest a way to solve this problem?

A. 1/5
B. 1/3
C. 2/5
D. 1/2
E. 2/3

MacFauz · Accepted Answer

Let weight of jar filled with beans = 100 g
Weight of jar = 20 g
Weight of coffee beans = 80 g
Weight of jar and remaining beans = 60 g
Weight of remaining beans = 40 g

Fraction remaining = 40/80 = 1/2

Answer is D.

Kudos Please... If my post helped.

chetan2u · Answer

Let weight of entire jar =  W_T  and weight after removing some beans =  W_{TN} 
and weight of beans =  W_B  and weight after removing some beans =  W_{BN} 
WEIGHT of jar =  W_J = 20% of W_T .......
so W_J = \frac{W_T}{5}.........W_B = \frac{4W_T}{5}........ 
if  W_{TN} = \frac{6W_T}{10}.................W_J remains constant, so W_{BN} = W_{TN} - W_J =\frac{6W_T}{10} - \frac{W_T}{5} = \frac{2W_T}{5}.....

we are looking for fraction of what is left = \frac{W_{BN}}{W_B} = \frac{2W_T}{5}/\frac{4W_T}{5} = \frac{1}{2}

D

fantaisie · Answer

Initial weight of a jar with coffee beans: C
Weight of an empty jar: J = 0.2C
Initial weight of the coffee beans: = 1C - 0.2C = 0.8C

Weight of a jar with coffee beans after the removal: 0.6C
Weight of the cofee beans after the removal: 0.6C - 0.2C = 0.4C

So we know now that initially we had 0.8C and now only 0.4C:  \frac{0.4}{0.8} = \frac{1}{2}

Answer:  D

AbdurRakib · Answer

fraction part of the beans remain in the jar=( \frac{60}{100} - \frac{20}{100} )/ \frac{80}{100} = \frac{40}{100} * \frac{100}{80} = \frac{1}{2}

Correct Answer D

law258 · Answer

The trick to this problem is realizing that the glass jar is representative of the glass jar + coffee beans. So once you figure out the weight of the jar, you can subtract it from the weight of jar + beans to figure out weight of the beans.

Say weight of jar + coffee = 100lb --> weight of jar = 20lb --> coffee = 80lb

weight of jar + coffee changes to 60lb --> weight of jar = 20 --> coffee = 40lb

40lb/80lb = 1/2

Kinshook · Answer

Given:
1. The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. 
2. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight.

Asked: What fraction part of the beans remain in the jar?

The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. 
Let the weight of coffee beans be x and weight of jar be y
y = 20% (x+y)
80%y = 20%x
y = .25x

After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight.
Let the fraction of beans remaining in the jar be k
y + kx = 60% (y+x)
.25x + kx = .6x + .6*.25x = .75x
kx = .5x
k = .5 = 1/2

IMO D

Kinshook · Answer

shahkevin99  please see the solution

bumpbot · Answer

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The weight of a glass of jar is 20% of the weight of the jar

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The weight of a glass of jar is 20% of the weight of the jar

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