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Posts: 6
Updated on: 25 Mar 2014, 01:08
Originally posted by tinashine20 on 26 Nov 2012, 04:03.
Last edited by Bunuel on 25 Mar 2014, 01:08, edited 1 time in total.
Last edited by Bunuel on 25 Mar 2014, 01:08, edited 1 time in total.
Added the OA.
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
76% (02:20) correct
24%
(02:29)
wrong
based on 325
sessions
History
Date
Time
Result
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The number 571+572+573 can be expressed as the products of 3 consecutive integers. What is the sum of these 3 consecutive integers?
A. 32
B. 33
C. 34
D. 35
E. 36
A. 32
B. 33
C. 34
D. 35
E. 36
tinashine20
571+572+573 = 3*572 = 3*(2^2*11*13) = 11*12*13 --> 11+12+13 = 36.
Answer: E.
P.S. Please provide OA's for the questions.
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mbaiseasy
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tinashine20
\(=571+572+573=1716=(13)(11)(2)(2)(3)\)
after seeing 11 and 13, I knew the third should be 12 without calculating rem. factors.
\(=11+12+13= 36\)
Answer: E
PareshGmat
Joined: 27 Dec 2012
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Concentration: General Management, Technology
WE:Information Technology (Computer Software)
Posts: 1,531
Addition of any 3 consecutive numbers is always divisible by 3
So, options A, C , D are ruled out
Now focus on options 33 & 36
It can be either
10, 11, 12 (Gives zero at the end after multiplication; ignore this series)
or
11, 12, 13 (Matches fine)
Answer = E
So, options A, C , D are ruled out
Now focus on options 33 & 36
It can be either
10, 11, 12 (Gives zero at the end after multiplication; ignore this series)
or
11, 12, 13 (Matches fine)
Answer = E
bhatiavai
Joined: 07 Dec 2009
Last visit: 28 Aug 2018
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Posts: 66
571+572+573 = 1716 = 2*2*3*11*13 = 12*11*13
11+12+13 = 36
11+12+13 = 36
Posts: 74
571 + 572 + 573 can be written as
572 -1 + 572 + 572 + 1 = 3*572 = 3 * 4 * 11 * 13 = 11 * 12 * 13...
Ans. E
572 -1 + 572 + 572 + 1 = 3*572 = 3 * 4 * 11 * 13 = 11 * 12 * 13...
Ans. E
petrified17
\(571+572+573 = 1716\)
Now, \(1716 = 11*12*13\)
So \(11+12+13=36\)
Option \(E\)
Posts: 13
niks18
how did you derive 11*12*13 from 1716?
petrified17
Hi petrified17
Factorize 1716, you will get 2*2*3*11*13. so it is evident that the three consecutive numbers has to be 11, 12 & 13
Another method is to note that the sum of these three will end in 6.
If product of 3 consecutive integers ends in 6, the units digits of integers would be either 1, 2, 3 or 6, 7, 8.
The units digit of sum of the units digits 1, 2, 3 would be 6 giving only possible answer 36.
The units digit of sum of the units digits 6, 7, 8 would be 1 which is not there in the options.
Posted from my mobile device
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If product of 3 consecutive integers ends in 6, the units digits of integers would be either 1, 2, 3 or 6, 7, 8.
The units digit of sum of the units digits 1, 2, 3 would be 6 giving only possible answer 36.
The units digit of sum of the units digits 6, 7, 8 would be 1 which is not there in the options.
Posted from my mobile device
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tinashine20
Another approach:
Sum of 3 consecutive integers is 3n + 3.
Subtracting 3 from each of the answer choices, we can eliminate A, C, D as they will not be divisible by 3. We are left with B and E.
B) 33 = 3n + 3 => n = 10
E) 36 = 3n + 3 => n = 11
Since the sum of 571, 572 and 573 gives a unit digit of 6, n cannot be 10 so we can eliminate answer choice B.
We are left with answer choice E.
Tushar2804
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WE:Supply Chain Management (Manufacturing)
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My take on this question was to focus on the last integer of the sum of the 3 numbers. It is 6.
In all the options given, except E there is no other option that satisfies both the conditions - product of consecutive integers and also the units digits of the product being 6.
So yes, E is the only possible answer.
In all the options given, except E there is no other option that satisfies both the conditions - product of consecutive integers and also the units digits of the product being 6.
So yes, E is the only possible answer.
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