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Great Explanation! Thanks....
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Interesting question. Let's try a different approach.

You should recall the following two formulas :

\((a+b)^2 = a^2 + 2ab + b^2\)
\((a-b)^2 = a^2 - 2ab + b^2\)

Using what is given in the question stem, we get :

\(a^2 + 2ab + b^2 = (a+b)^2 = x^2\)
\(a^2 - 2ab + b^2 = (a-b)^2 = y^2\)

Substracting the two equations yields : \(4ab = x^2 - y^2\) meaning that \(ab = \frac{(x^2 - y^2)}{4}\).

Multiply the result by 3 and we get \(3ab = \frac{3(x^2 - y^2)}{4}\)

Which is answer choice A.

Hope that helped :-D
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plugging numbers is quite fast in this case:
Let
a=1
b=2

Then; x= 1+2=> 3 and Y= 1-2=> -1

Question asks 3ab=.........
As our number 3ab= 3*1*2=6

now plug the value of x and y in the answer choices. Option A gives 6 and that is the number we need.

Hence: Ans is A.

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a=x+y/2; b=x-y/2;3ab=3(x^2-y^2/4)= A
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Excellent question. saving it in my notebook to try later.
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Plugging values is another method, you can use to solve this one!
Let a=3, b=2, x = 3+2 = 5
Similarly y = 3-2 = 1

We know that 3ab = 3*2*3 = 18

Of the answer options,
A. (3x^2 - 3y^2)/4 = 3(25) - 3(1)/4 = 75 - 3/4 = 18
B. (3y^2 - 3x^2)/4 = 3(1) - 3(25)/4 = 3 - 75/4 = -18
C. 3x+3y/2 = 3(5) + 3(1)/2 = 9
D. 3x - 3y/2 = 3(5) - 3(1)/2 = 6
E. 3x^2 - 3y^2/2 = 3(25) - 3(1)/2 = 73 - 3/2 = 36

Hence, Option A is the answer.
If you started with evaluating the first choice, it wouldn't take much time to find the answer.
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