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The combined salaries of three brothers is $90,000. Mr. Big earns twice what Mr. Small earns, and Mr. Middle earns 1 1/2 times what Mr. Small earns. What is the smallest salary of the three brothers?

Let assume Mr Small= X
Now Mr big Earns Twice Which Means= 2X
Now For Middle one= X*1/2

X+2x+x*1/2=90

Answer B is correct.
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B + S + M = $90,000

B = 2S
M = 3S/2

2S + S + 3S/2 = $90,000
4S + 2S + 3S = $180,000
S = $180,000/9 = $20,000. Ans - A.
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The combined salaries of three brothers is $90,000. Mr. Big earns twice what Mr. Small earns, and Mr. Middle earns 1 1/2 times what Mr. Small earns. What is the smallest salary of the three brothers?

Let the salary for Mr. Small be \(x\)

\(2x + 1.5x + x = 90,000\)

\(4.5x = 90,000\)

\(x = 20,000\)

Hence, Answer is A
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The combined salaries of three brothers is $90,000. Mr. Big earns twice what Mr. Small earns, and Mr. Middle earns 1 1/2 times what Mr. Small earns. What is the smallest salary of the three brothers?

(A) 20,000
(B) 22,000
(C) 25,000
(D) 30,000
(E) 40,000

We can let the salaries of Mr. Big, Mr. Small, and Mr. Medium = B, S, and M, respectively, and create the equations:

B + S + M = 90,000

and

B = 2S

and

M = 1.5S

Substituting, we have:

2S + S + 1.5S = 90,000

4.5S = 90,000

S = 20,000

Answer: A
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