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Updated on: 04 Dec 2014, 22:29
Originally posted by PareshGmat on 04 Dec 2014, 00:41.
Last edited by PareshGmat on 04 Dec 2014, 22:29, edited 1 time in total.
Last edited by PareshGmat on 04 Dec 2014, 22:29, edited 1 time in total.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
59% (01:14) correct
41%
(01:10)
wrong
based on 380
sessions
History
Date
Time
Result
Not Attempted Yet
How many multiples of 7 are there between 21 and 343, exclusive ?
A. 48
B. 47
C. 46
D. 45
E. 44
A. 48
B. 47
C. 46
D. 45
E. 44
02 Dec 2017, 15:16
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PareshGmat
ASIDE: there are various formulas that students can memorize for this kind of question. Here's a solution that uses a nice easy rule (which can be applied in many ways):
The number of integers from x to y inclusive equals y - x + 1
exclusive: so, we're not going to count 21 and 343
The multiples of 7 to be counted are:
28
35
42
.
.
.
336
We can REWRITE the values as follows:
28 = (7)(4)
35 = (7)(5)
42 = (7)(6)
.
.
.
336 = (7)(48)
So, we need only find the number of integers from 4 to 48 inclusive
Applying the above rule, the number of integers = 48 - 4 + 1 = 45
Answer: D
Cheers,
Brent
General Discussion
04 Dec 2014, 12:39
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1. Find out how many numbers are between 21 and 343. 343 - 21 = 322.
2. 322/7 = 46 multiples of 7 between 21 and 343
Answer C!
2. 322/7 = 46 multiples of 7 between 21 and 343
Answer C!
