1st: Each of the 5 White Marbles are Identical. Each of the 5 Black Marbles are Identical.
However, since Each Girl and Each Boy is Distinct, it matters which Boy or Girl receives a Black or White Marble.
Probability = (No. of Favorable Ways in which the 5 Girls receive B-B-B-B-B or W-W-W-W-W-) / (Total No. of Ways to Distribute the 5 White and 5 Black Marbles among the 5 Girls and 5 Boys)
there are only 2 Favorable Outcomes ------> All 5 Girls receive the 5 Black -OR- All 5 Girls receive the 5 White
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DEN = Total No. of Ways to Distribute 5 Identical Whites and 5 Identical Blacks to -------> 5 Distinct Girls and 5 Distinct Boys
Case 1: All 5 Girls receive 5 White Marbles AND All 5 Boys receive 5 Black Marbles
"5 choose 5" * "5 choose 5" = 1 Way under this Scenario
Case 2:
4 Girls gets 4 White -AND- 1 Girl gets 1 Black
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We need to find all the different ways we can put together a Combination of 4 Girls to give the 4 Whites to. Once we give the 4 Whites away to the 4 Girls, the 5th Girl who gest the 1 Black will automatically be chosen.
we can do this in -----> "5 choose 4" No. of Ways = 5! / (4!)(1!) = 5 Ways
----AND----
1 Boys gets 1 White -AND- 4 Boys get 4 Black
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We need to shuffle around the 5 Different Ways for the Girls with all the Different ways we can pair off 4 Boys to give the 4 Black to. Again, once we chose 4 Boys for a given Combination, the 5th Boy who will receive the 1 White will automatically be chosen.
We can do this in: "5 choose 4" No. of Ways -----> 5 Ways
Case 2: 5 * 5 = 25 Different Ways to Distribute the marbles in this Scenario
Case 3:
3 Girls get White -AND- 2 Girls get Black
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Following the Same Logic, how many different ways can we group together 3 Girls to give the White to? Once we have chosen 3 Girls for any given Combination, the 2 Girls who receive the 2 Black will automatically be chosen.
we can do this in: "5 choose 3" No. of Ways -------> 5! / (3!)(2!) = 10 Different Ways
-AND-
2 Boys get 2 White -AND- 3 Boys get 3 Black
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for Each of the 10 Different Ways above, we can shuffle them around with the Number of Different Ways we can give 2 Whites to 2 Boys and 3 Black to 3 Boys. Each of the "shuffles" (i.e., arrangements) will constitute a Unique Distribution of the Marbles
once we choose which 2 Boys will receive 2 White, the 3 Boys who will get Black automatically get chosen.
we can do this in: "5 choose 2" No. of Ways = 5! / (2!)(3!) = 10 ways
Total No. of Unique Distributions under Scenario 3 =
10 * 10 = 100 Ways
Case 4, Case 5, and Case 6 follow the Same Logic as above. However, we just switch around the Black and White.
Case 4:
2 Girls get 2 White -AND- 3 Girls get 3 Black
---AND---
3 Boys get 3 White -AND- 2 Boys get 2 Black
100 Ways
Case 5:
25 Ways
Case 6:
1 Way in which the Girls receive NO Whites (5 Black)
and
1 Way in which the Boys receive 5 Whites (NO Black)
1*1 =
1 Ways
All the Different Ways to Distribute = DEN = Sum of All 6 Cases =
1 + 25 + 100 + 100 + 25 + 1 = 252
Probability = (2/252) = 1/126
-A-