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Bunuel
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Answer = C = 80

Refer Venn diagram below:

Attachment:
squ.png
squ.png [ 5.94 KiB | Viewed 6281 times ]

Total = 40 + 10 + 7 + 23 = 80
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W+R+B=
-All cars with one feature counted once
-All cars with two features counted twice
-All cars with all features counted thrice

When we correct for the twice we subtract cars with two features

As we know that two features will include cars having all features in each of the three combinations of two features cars. So we end subtracting all the cars with all features therefore we add the count of cars with three feature

So
W+R+B-W&B-W&R-R&B+W&B&R
40+50+30-13-17-21+11=80.

Posted from my mobile device
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Bunuel
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.

Hi!
Do you have the official answer? Because I find 47 which is not included in answer choices. To me the correct formula is: Total= 40 + 30 + 50 - 21 - 13 - 17 - 2(11) = 47 Is that right?
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Bunuel
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.

Hi!
Do you have the official answer? Because I find 47 which is not included in answer choices. To me the correct formula is: Total= 40 + 30 + 50 - 21 - 13 - 17 - 2(11) = 47 Is that right?
Hi the formula you are applying is when the intersections are "exactly two group overlaps" . This question includes"sum of two group overlaps".
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Hey! It is really interesting task) My answer - 80
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Malbash212
Bunuel
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.

Hi!
Do you have the official answer? Because I find 47 which is not included in answer choices. To me the correct formula is: Total= 40 + 30 + 50 - 21 - 13 - 17 - 2(11) = 47 Is that right?
Hi the formula you are applying is when the intersections are "exactly two group overlaps" . This question includes"sum of two group overlaps".

Thank you for your answer. Is it different from this one: https://gmatclub.com/forum/there-are-70 ... 97623.html
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Malbash212

Yes ! You got that right. Learn this formula, under exam conditions you will not get it right. Trust me on that. best of luck
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Bunuel
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.
­

For this question why cant i use the formula:
Total= A+B+C- {exactly 2} - 2{All 3 option}

so to find total i ccan use 2 formulas?
Total =A+B+C- {exactly 2} + {all 3}
and
Total= A+B+C- {exactly 2} - 2{All 3 option}
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Hi, coming back to this after a year but I have the same doubt. Why didn't we subtract 2x11 instead of 11? When to use the formula 2x(all 3) and JUST (all 3)?
harshchougule
Bunuel
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.
­

For this question why cant i use the formula:
Total= A+B+C- {exactly 2} - 2{All 3 option}

so to find total i ccan use 2 formulas?
Total =A+B+C- {exactly 2} + {all 3}
and
Total= A+B+C- {exactly 2} - 2{All 3 option}
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Bunuel
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sanskritixk
Hi, coming back to this after a year but I have the same doubt. Why didn't we subtract 2x11 instead of 11? When to use the formula 2x(all 3) and JUST (all 3)?
harshchougule
Bunuel
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.
­

For this question why cant i use the formula:
Total= A+B+C- {exactly 2} - 2{All 3 option}

so to find total i ccan use 2 formulas?
Total =A+B+C- {exactly 2} + {all 3}
and
Total= A+B+C- {exactly 2} - 2{All 3 option}

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