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At a certain dealership, every car on the lot has at least one of the

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At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 22 Jan 2015, 06:27
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A
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Difficulty:

  45% (medium)

Question Stats:

65% (02:02) correct 35% (02:48) wrong based on 80 sessions

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At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.

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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 22 Jan 2015, 06:37
Bunuel wrote:
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.


total = Windows +brakes+radio -(Brk & rad +wind & brk + wind & radio ) + all 3
=40+30+50-(21+13+17)+11
=80
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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 22 Jan 2015, 23:18
Yup 80

Used same Gclub formula as mentioned above
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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 23 Jan 2015, 00:49
1
Answer = C = 80

Refer Venn diagram below:

Attachment:
squ.png
squ.png [ 5.94 KiB | Viewed 1434 times ]


Total = 40 + 10 + 7 + 23 = 80
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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 23 Jan 2015, 06:40
W+R+B=
-All cars with one feature counted once
-All cars with two features counted twice
-All cars with all features counted thrice

When we correct for the twice we subtract cars with two features

As we know that two features will include cars having all features in each of the three combinations of two features cars. So we end subtracting all the cars with all features therefore we add the count of cars with three feature

So
W+R+B-W&B-W&R-R&B+W&B&R
40+50+30-13-17-21+11=80.

Posted from my mobile device
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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 18 Jan 2019, 05:43
Bunuel wrote:
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.


Hi!
Do you have the official answer? Because I find 47 which is not included in answer choices. To me the correct formula is: Total= 40 + 30 + 50 - 21 - 13 - 17 - 2(11) = 47 Is that right?
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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 18 Jan 2019, 06:14
1
Malbash212 wrote:
Bunuel wrote:
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.


Hi!
Do you have the official answer? Because I find 47 which is not included in answer choices. To me the correct formula is: Total= 40 + 30 + 50 - 21 - 13 - 17 - 2(11) = 47 Is that right?

Hi the formula you are applying is when the intersections are "exactly two group overlaps" . This question includes"sum of two group overlaps".
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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 18 Jan 2019, 07:02
Hey! It is really interesting task) My answer - 80
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New post 18 Jan 2019, 07:30
ShankSouljaBoi wrote:
Malbash212 wrote:
Bunuel wrote:
At a certain dealership, every car on the lot has at least one of the three modest options: windows, brakes and radio. 40 cars have windows, 30 have brakes, and 50 have a radio. 21 cars have brakes and radio, 13 have windows and brakes. 17 have windows and radio. If 11 cars have all 3 options, what is the total number of cars on the lot ?

A. 69
B. 70
C. 80
D. 91
E. 120

Kudos for a correct solution.


Hi!
Do you have the official answer? Because I find 47 which is not included in answer choices. To me the correct formula is: Total= 40 + 30 + 50 - 21 - 13 - 17 - 2(11) = 47 Is that right?

Hi the formula you are applying is when the intersections are "exactly two group overlaps" . This question includes"sum of two group overlaps".


Thank you for your answer. Is it different from this one: https://gmatclub.com/forum/there-are-70 ... 97623.html
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Re: At a certain dealership, every car on the lot has at least one of the  [#permalink]

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New post 18 Jan 2019, 07:37
Malbash212

Yes ! You got that right. Learn this formula, under exam conditions you will not get it right. Trust me on that. best of luck
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Even if it takes me 30 attempts, I am determined enough to score 740+ in my 31st attempt. This is it, this is what I have been waiting for, now is the time to get up and fight, for my life is 100% my responsibility.

Dil ye Ziddi hai !!!

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Re: At a certain dealership, every car on the lot has at least one of the   [#permalink] 18 Jan 2019, 07:37
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