If y = 2 + 2K and y#0, then 1/y + 1/y + 1/y + 1/y = ?

Question

If y = 2 + 2K and  y
eq{0} , then 1/y + 1/y + 1/y + 1/y = ?

A. 1/(8+8k)
B. 2/(1+k)
C. 1/(8+k)
D. 4/(8+k)
E. 4/(1+k)

KarishmaB · Accepted Answer

You should give the options.

1/Y + 1/Y + 1/Y + 1/Y 
= 4/Y 
= 4/(2 + 2K) 
= 2/(1 + K)

EMPOWERgmatRichC · Answer

Hi zatspeed,

This prompt can be solved in a couple of different ways. While most Test Takers would probably take an Algebraic approach, you can solve it by TESTing VALUES.

We're told that Y = 2 + 2K. We're asked for the value of 1/Y + 1/Y + 1/Y + 1/Y.

While I normally would NOT TEST 0 or 1, the answer choices are sufficiently different from one another that using those numbers would not be a problem here....

IF....
K = 0
Y = 2+0 = 2
The answer to the question is 1/2 + 1/2 + 1/2 + 1/2 = 2

So we're looking for an answer that = 2 when K = 0.

Answer A: 1/(8+0) = 1/8 This is NOT a match
Answer B: 2/(1+0) = 2 This IS a match
Answer C: 1/(8+0) = 1/8 This is NOT a match
Answer D: 4/(8+0) = 1/2 This is NOT a match
Answer E: 4/(1+0) = 4 This is NOT a match

Final Answer:  B

GMAT assassins aren't born, they're made,
Rich

zatspeed · Answer

Sorry, I have updated it now.

KarishmaB · Answer

Responding to a pm:

The question gives you that 
 Y = 2 + 2K

So you simply substitute that in place of Y in the denominator.

\frac{4}{Y} = \frac{4}{(2 + 2K)}

Then just take 2 common from the numerator and denominator to get:

\frac{4}{(2 + 2K)} = \frac{2*2}{2(1 + K)}

Cancel off the 2 of the numerator with the 2 of the denominator to get:

\frac{2*2}{2(1 + K)} = \frac{2}{(1 + K)}

Shiv2016 · Answer

y=2(1+k)
4(1/y)= 4(1/2(1+k))= 2/(1+k)

mbaapp1234 · Answer

y = 2+2k

1/y +1/y + 1/y+1/y = 4/y

4/(2+2k) = 2/(1+k)

MHMBA2019 · Answer

y= 2+ 2k

1/y+1/y+1/y+1/y= 4/y
plug 2+2k in for y
4/2+2k--> simplify to 2/1+K

ScottTargetTestPrep · Answer

Adding the given fractions we have:

4/y

Since y = 2 + 2k, we have:

4/(2 + 2k) = 4/  = 2/(1 + k)

Answer: B

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If y = 2 + 2K and y#0, then 1/y + 1/y + 1/y + 1/y = ?

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If y = 2 + 2K and y#0, then 1/y + 1/y + 1/y + 1/y = ?

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