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Bunuel
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Bunuel
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Hi Bunuel,

Should this question include a picture?

GMAT assassins aren't born, they're made,
Rich
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EMPOWERgmatRichC
Hi Bunuel,

Should this question include a picture?

GMAT assassins aren't born, they're made,
Rich

Added the image. Thank you.
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The area of larger shaded square = 9*The area of smaller shaded square => The side of larger shaded = 3*The side of larger shaded => The side of smaller shaded square = 1/4 * side of ABCD.

Area of ABCD = 25 => Its side = 5 => The side of smaller shaded square = 1/4*5=5/4
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Area in the ratio => 9:1
Sides then will be in the ratio => 3:1
Diagonals hence will be in the ratio => 3:1
Diagonal of the bigger square is 5 * \sqrt{2}
Hence, Diagonal of the shaded smaller square, (side * \sqrt{2}) => 1/4*(5 * \sqrt{2})
Therefore, side of the shaded smaller square => 5/4
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If the area of square ABCD = 25, then each side = 5

Attachment:
4squaresinasquare_text.PNG
4squaresinasquare_text.PNG [ 2.28 KiB | Viewed 22972 times ]

Say side of small square = x

Given that \(9x^2 = (5-x)^2\)

\(8x^2 + 10x - 25 = 0\)

\(8x^2 + 20x - 10x - 25 = 0\)

4x(2x + 5) - 5(2x+5) = 0

(4x-5)(2x+5) = 0

\(x = \frac{5}{4}\)

Answer = B
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Bunuel
Attachment:
4squaresinasquare_text.PNG
If square ABCD has area 25, and the area of the larger shaded square is 9 times the area of the smaller shaded square, what is the length of one side of the smaller shaded square? Note: Figure not drawn to scale

A. 3/4
B. 5/4
C. 6/5
D. 4/3
E. 5/3

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let a and A be the sides of smaller and larger square.
area of smaller square = a^2
of larger square=A^2
ATQ !!
A^2=9a^2
A=3a
A+a=5
4a=5
a=5/4
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Let the length of the smaller side be x. As per the question, 9*x*x=(5-x)*(5-x). x comes to 5/4. Option B it is !
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