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Bunuel
If (12z)/(5 – 6y/x) = 4z then which of the following is true?

(A) 2x = 3y
(B) 3x = 2y
(C) x = 3y
(D) 3x = y
(E) 2x = y


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12z/(5-6y/x=4z
3x=5x-6y
2x=6y
x=3y

Answer: C
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\(\frac{12z}{(5 - 6y/x)}\)= 4z

=> \(\frac{12xz}{(5x-6y)}\)=4z

=> 12x = 20x - 24y
x=3y

Ans C
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12zx/5x-6y = 4z
3x=5x-6y
6y=2x
3y=x or x=3y
Answer C
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Bunuel
If (12z)/(5 – 6y/x) = 4z then which of the following is true?

(A) 2x = 3y
(B) 3x = 2y
(C) x = 3y
(D) 3x = y
(E) 2x = y


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VERITAS PREP OFFICIAL SOLUTION

This problem could involve a lot of algebra that would be time consuming. Note that you could re-write the problem replace the complex denominator as something.

12z/something = 4z
something = 3

We now know that the complex denominator = 3.

5 – 6y/x = 3

Now we can substitute something for 6y/x, such that we are left with:

5 – something = 3
something = 2

This leave us with our fraction = 2. With some simple algebra we can now solve for the relationship between x and y.

6y/x = 2
6y = 2x
3y = x

The answer is C.
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rachitsinha
\(\frac{12z}{(5 - 6y/x)}\)= 4z

=> \(\frac{12xz}{(5x-6y)}\)=4z

=> 12x = 20x - 24y
x=3y

Ans C

rachitsinha Could you explain to me why in this part:

6y is not becoming 6yx?

\(\frac{12z}{(5 - 6y/x)}\)= 4z

=> \(\frac{12xz}{(5x-6y)}\)=4z

Bunuel or could you clarify?
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