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12 Jul 2015, 00:33
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
50% (01:26) correct
50%
(01:46)
wrong
based on 182
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure, All the lines are representing the network of roads and one can walk on these roads only to reach from one point to another in the grid.
In How many ways can a person reach from Point A to Point B using the shortest possible path? (only rightward or upward movements are allowed i.e. left and down movements are not allowed)
A) 8
B) 10
C) 12
D) 15
E) More than 15
"Kudos" for correct Solution
In How many ways can a person reach from Point A to Point B using the shortest possible path? (only rightward or upward movements are allowed i.e. left and down movements are not allowed)
A) 8
B) 10
C) 12
D) 15
E) More than 15
"Kudos" for correct Solution
Attachments
File comment: www.GMATinsight.com
Question.jpg [ 23.25 KiB | Viewed 4039 times ]
ENGRTOMBA2018
Joined: 20 Mar 2014
Last visit: 01 Dec 2021
Posts: 2,319
Given Kudos: 816
Concentration: Finance, Strategy
Schools: Kellogg '18 (M)
GMAT 1: 750 Q49 V44
GPA: 3.7
WE:Engineering (Aerospace and Defense)
Products:
12 Jul 2015, 03:16
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GMATinsight
Let the desired path be APQRCSB (refer to attached image)
Let R and U represent Right and Up direction movements.
Thus, we get the following arrangement when we go from A to B: RRRRUU
This given arrangement can be arranged in : 6! / (4!*2!) = 15 ways. 6! to represent arrangement of 6 letters, 4! and 2! represent duplicated arrangements caused by 4 identical 'R's and 2 identical 'U's respectively.
Thus D is the correct answer.
Attachments
Arrangements.jpg [ 15.3 KiB | Viewed 3971 times ]
12 Jul 2015, 03:59
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GMATinsight
steps required for shortest path is 6,where there are total 2 upwards move and 4 right wards move..
so total ways =6!/2!4!=15
ans D
