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Bunuel
When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

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Let n =5q+3 ---> n =8 must satisfy the given question as n can be any number of the form n =5q+3

Thus rem when (8+4)^2 = 144 is divided bny 5 = 4. E is the correct answer.
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n must be of the form 5(x)+3, where x is an integer.

[(5x+3)+4]^2 = (5x+7)^2 = 25x^2 + 70x + 49.

For x = 1: 25(1) + 70(1) + 49 = 144.

Remainder when 144 is divided by 5 will be 4.

Hence, Ans (E).
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Bunuel
When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

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I plugged in n=8. (When dividing 8/5 = 1 and Remainder is 3)

Now plug in 8 in (n + 4)^2 >>> 12^2/5 = 28 with a remainder of 4

Answer E
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Bunuel
When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

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The first sentence says:
n=5x+3

Therefore, n can be 3, 8, 13, etc.

(3+4)^2 = 49, remainder is 4.
(8+4)^2 = 144, remainder is 4.

E
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Bunuel
When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

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n can be 3,8,13,18 and so on

(n+4)^2=49,144,289 and so on.
Remainder =4 when divided by 5
Answer E
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Bunuel
When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

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800score Official Solution:

When n is divided by 5 the remainder is 3. So n = 5k + 3, where k is some non-negative integer. (n + 4)² = (5k + 7)² = 25k² + 70k + 49 = 5(5k² + 14k + 9) + 4. Therefore when (n + 4)² is divided by 5 the remainder is 4. The right answer is (E).

Another option is to plug in n = 3. We can do so under an assumption that the remainder must be the same for ANY n, which yields 3 as the remainder when divided by 5.
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n = 5+3 = 8

i.e. n+4 = 8+4 = 12

12^2 = 144

E
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one possible value of n = 5+3 = 8

i.e. n+4 = 8+4 = 12

12^2 = 144

144 when divided by 5 leaves remainder 4

Answer: Option E
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Solution


    • When n is divided by 5 the remainder is 3

To find
    • The remainder when (n + 4)^2 is divided by 5

Approach and Working out
    • (n+4)^2 = n^2 +16 +8n
    • (n^2 +16 +8n /5)R = (n^2/5)R + (16/5)R + (8n /5)R
    • = (9/5)R + 1 + (24/5)R
    • =(4 +1 +4/5)R =(9/5)R
    • = 4

Hence, option E is the correct answer.

Correct Answer: Option E
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Since it is a PS question, it will have a unique answer for any n which gives the remainder of 3 when divided by 5.
So, we can take any n which gives the remainder of 3 when divided by 5.
Let us take the smallest positive n = 3
Now, (n + 4)^2 = (3+4)^2 = 49
49/5 remainder = 4

Answer = E


Bunuel
When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

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Bunuel
When n is divided by 5 the remainder is 3. What is the remainder when (n + 4)^2 is divided by 5?

A. 0
B. 1
C. 2
D. 3
E. 4

Kudos for a correct solution.

Given: When n is divided by 5 the remainder is 3.

Asked: What is the remainder when (n + 4)^2 is divided by 5?

n = 5k + 3
n+4 = 5k + 3 + 4 = 5(k+1) + 2

(n+4)^2mod5 = 2^2mod5 = 4

IMO E
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N/5 R 3
(N+4)/5 R 2
(N+4)/5. X (N+4)/5 reminder 2x2 = 4

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Let's solve the problem using two methods

Method 1: Substitution

When n is divided by 5 the remainder is 3.

Dividend = Divisor * Quotient + Remainder

Let n = 5*0 + 3 = 3

What is the remainder when (n + 4)^2 is divided by 5?
=> (n + 4)^2 = (3 + 4)^2 = 49

=> Remainder of (n + 4)^2 by 5 = Remainder of 49 by 5 = 4

Method 2: Algebra

When n is divided by 5 the remainder is 3.

Dividend = Divisor * Quotient + Remainder

=> n = 5*k + 3 (where k is an integer)
=> n = 5k + 3

What is the remainder when (n + 4)^2 is divided by 5?
=> (n + 4)^2 = (5k + 3 + 4)^2 = (5k + 7)^2 = 25\(k^2\) + 2*5k*7 + \(7^2\)

=> Remainder of 25\(k^2\) + 2*5k*7 + \(7^2\) by 5 = Remainder of 25\(k^2\) by 5+ Remainder of 2*5k*7 by 5 + Remainder of 49 by 5 = 0 + 0 + 4 = 4

So, Answer will be E
Hope it helps!

Watch the following video to MASTER Remainders

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