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Sub 505 (Easy)|   Percent and Interest Problems|   Word Problems|                           
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Bunuel
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Video solution from Quant Reasoning:
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Bunuel
A manufacturer of a certain product can expect that between 0.3 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?

(A) Between $15,000 and $25,000
(B) Between $30,000 and $50,000
(C) Between $60,000 and $100,000
(D) Between $150,000 and $250,000
(E) Between $300,000 and $500,000


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Units are expected to be defective: 0.3/100*20,000 => 0.5/100*20,000: 60 ~ 100

=> Between $150,000 and $250,000

Ans: D
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(.5/100)*20,000*2,500=250,000. Only D has this as the higher limit. No need to calculate for .3%
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let x be the percent of the defective units
0.3<x<0.5
we can assume that x can be 0.4
since its 0.4 percent this would be \(\frac{0.4}{100}\)
0.4 percent of the 20,000 units given is the same as:

20,000*\(\frac{0.4}{100}\)= 80 units

so, about 80 units of the 20000 given will be defective, hence the manufacturer can expect to need to recover around:

80*2500= $200,000
since 200,000 fits in the $150,000 and $250,000 range.

Answer is D
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0.3 percent is 3 per thousand. 3 per thousand of 20 thousand is 3 x 20 = 60.

Lower bound for total price of defective units: 60 x 2.5 thousand = 150 thousand.

Thus D is the correct answer choice.
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If you look at the answer format, you can easily notice that all maximum values are different (also calculating 0.5% will cancel out easier than 0.3%)

Thus maximum refund to expect = 0.5% x 2,500 x 20,000 = 250,000
Answer D

Hint: 0.5% x 20,000 x 2500 = 0.5 x 20000 x 2500/100 = 10,000 x 25 = 250,000
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How much money need to cover for refund ?
Number of units = 20,000 units
cost = 2500$ / unit
0.3% of units = 3/1000 x 20,000 = 60 units defective
0.5% of units = 5/1000 x 20,000 = 100 units defective
Between 60x2500$ = 150,000$
100x2500$ = 250,000$
D
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Bunuel
A manufacturer of a certain product can expect that between 0.3 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?

(A) Between $15,000 and $25,000
(B) Between $30,000 and $50,000
(C) Between $60,000 and $100,000
(D) Between $150,000 and $250,000
(E) Between $300,000 and $500,000

If at least 0.3 percent of the 20,000 units are defective, then at least 0.3/100 x 20,000 = 60 units will be defective costing 60 x 2,500 = 150,000 dollars.

Since we see that 150,000 is the “low” number and only answer choice D has 150,000 as the low number, answer choice D must be correct.

Answer: D
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Bunuel
A manufacturer of a certain product can expect that between 0.3 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?

(A) Between $15,000 and $25,000
(B) Between $30,000 and $50,000
(C) Between $60,000 and $100,000
(D) Between $150,000 and $250,000
(E) Between $300,000 and $500,000


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ok here is a quick method :)

remove all zeros 2,500 = 25
and 20,000 = 2

total number of units 25*2 = 50

now add remaining number of zeros ( add six zeros) :) 50, 000, 000

5*3 = 15 and 5*5 = 25

so answer is D :)
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Bunuel
A manufacturer of a certain product can expect that between 0.3 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?

(A) Between $15,000 and $25,000
(B) Between $30,000 and $50,000
(C) Between $60,000 and $100,000
(D) Between $150,000 and $250,000
(E) Between $300,000 and $500,000


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All the upper limits are different (and easier to calculate).

20,000 Units. 1% is 200. 0.5% is 100 units.

Refund is full amount so 100*2500. That's 4 zeros.

Option E.
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Bunuel
A manufacturer of a certain product can expect that between 0.3 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?

(A) Between $15,000 and $25,000
(B) Between $30,000 and $50,000
(C) Between $60,000 and $100,000
(D) Between $150,000 and $250,000
(E) Between $300,000 and $500,000

I don't how the experts will suggest but I want to calculate the either lower limit or the upper limit to save time. Because there is no second match for either limit. For example,

The Lower defective level is \(20,000*\frac{3}{100*10}=60\); the amount \( 60*2,500=150,000\) only one match with the answer choice. (D)

The upper defective level is \(\frac{20,000*5}{100*10}=100\); the amount \(100*2,500=250,000\) only one match with the answer choice (D)

The answer is \(D\)
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Bunuel
A manufacturer of a certain product can expect that between 0.3 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?

(A) Between $15,000 and $25,000
(B) Between $30,000 and $50,000
(C) Between $60,000 and $100,000
(D) Between $150,000 and $250,000
(E) Between $300,000 and $500,000


Answer: Option D

Video solution by GMATinsight

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Bunuel
A manufacturer of a certain product can expect that between 0.3 percent and 0.5 percent of the units manufactured will be defective. If the retail price is $2,500 per unit and the manufacturer offers a full refund for defective units, how much money can the manufacturer expect to need to cover the refunds on 20,000 units?

(A) Between $15,000 and $25,000
(B) Between $30,000 and $50,000
(C) Between $60,000 and $100,000
(D) Between $150,000 and $250,000
(E) Between $300,000 and $500,000


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Number of units that can be defective is between
\(\frac{0.3}{100}*20000 = 60\) and
\(\frac{0.5}{100}*20000 = 100\)

the retail price is $2,500 per unit

So, expected refunds is between
60*2500 = 150,000 and
100*2500 = 250,000

so, D is the answer.
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