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Bunuel
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When we reverse the diagram for simplicity, the triangles formed have the following co-ordinates

Attachment:
Inverted diagram.png
Inverted diagram.png [ 2.67 KiB | Viewed 5197 times ]

The shaded region's area is difference in the areas of the larger triangle and the smaller triangle

Area(larger triangle) = \(\frac{1}{2}*3*3 = \frac{9}{2}\)
Area(smaller triangle) = \(\frac{1}{2}*1*1 = \frac{1}{2}\)

Therefore, the area of the shaded region is \(\frac{9}{2} - \frac{1}{2} = \frac{8}{2} = 4\)(Option B)
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Is my approach right to get the value of Y?
as it is given that y = x − 3
and we know that Li intersect L2 at x = 2 then putting the value of x in above equation we can get the value of Y and that is -1...am i doing some mistake?
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sananoor
Is my approach right to get the value of Y?
as it is given that y = x − 3
and we know that Li intersect L2 at x = 2 then putting the value of x in above equation we can get the value of Y and that is -1...am i doing some mistake?
sananoor What your doing is perfectly correct. the co-ordinates in clockwise are (0,0) (2,0) (3,0) (2,-1) (0,-3)
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Bunuel

In the coordinate plane above, if the equation of ℓ1 is y = x − 3 and the equation of ℓ2 is x = 2, then what is the area of the shaded region?

(A) 3
(B) 4
(C) \(3 \sqrt{2}\)
(D) 4.5
(E) 5

Attachment:
2016-01-04_0026.png

Identify all the boundary values

From clockwise, x axis -> 2,0 2,-1 -3,0 & 0,0

Put x = 0 in l1, to get y =-3

Area of trapezium = 1/2 * 4 * 2 (sum of || sides * height * 1/2)
= 4

B
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