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Bunuel
If x = 3y, where y is a prime number greater than 2, how many different positive even divisors does x have, including x?

A. 0
B. 1
C. 2
D. 3
E. It cannot be determined from the information given


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x = 3y and y is a prime greater than 2
This means that y will always be an odd number.

Hence x = 3*odd = odd
An odd number does not have any even numbers as factors.
Option A
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from the question stem X can never have an even divisor
because
X= 3*y
X = odd * (prime>2) .... all primes greater than 2 are odds
=> X = odd * odd
X = odd
hence it cannot have a positive even divisor
ANS: A
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Since Y is prime greater than 2, Y has to be ODD
since ODD X ODD is always ODD 3Y is ODD
Thus there are no even factors

Ans:A

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SINCE x=3y, here for y to be a prime number greater than 2, the factors of x will always be odd,
we can assume values and check,when y=3: x=3*3=9
when y=5: x=3*5=15
.
.
.
when y=19: x=3*19=57
Hence each of this will have positive odd factors. Thus OA is A
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An odd number multiplied by an odd number yields an odd number.
Also an odd number can never be divisible by an even number.
Hence as y is an odd number (all primes>2 are odd)=> x must be odd=> Zero even divisors.
Hence A
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x = 3y
Y is a odd prime number : 3,5,7
x always results only odd number
0 positive even
A
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Bunuel
If x = 3y, where y is a prime number greater than 2, how many different positive even divisors does x have, including x?

A. 0
B. 1
C. 2
D. 3
E. It cannot be determined from the information given


Kudos for correct solution.

We can pick simple numbers

x= 3(5)

or

x=3(3)

In either case there are 0 even numbers- for the first example 1 3 5 15- in the second example, 1 3 9- no even numbers

Thus
"A"
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