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03 Mar 2016, 18:27
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
51% (02:09) correct
49%
(02:21)
wrong
based on 265
sessions
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Not Attempted Yet
In a hiring procedure, applicants should be recommended by three interviewers. Of 30 applicants, 15 applicants were recommended by the first interviewer. 17 applicants were recommended by the second interviewer. 20 applicants were recommended by the third interviewer. What is the possible least number of the applicants recommended by all of the three interviewers?
A. 0
B. 2
C. 4
D. 5
E. 10
* A solution will be posted in two days.
A. 0
B. 2
C. 4
D. 5
E. 10
* A solution will be posted in two days.
05 Mar 2016, 08:27
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MathRevolution
Please find the solution in the image attached
Attachments
www.GMATinsight.com.jpg [ 77.13 KiB | Viewed 4808 times ]
General Discussion
06 Mar 2016, 03:47
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In a hiring procedure, applicants should be recommended by three interviewers. Of 30 applicants, 15 applicants were recommended by the first interviewer. 17 applicants were recommended by the second interviewer. 20 applicants were recommended by the third interviewer. What is the possible least number of the applicants recommended by all of the three interviewers?
A. 0
B. 2
C. 4
D. 5
E. 10
SET.jpg [ 7.15 KiB | Viewed 4753 times ]
->The above picture is possible. 20 applicant by the third interviewer avoid intersection and can be divided by each 10 for the first interviewer and the other 10 for the second interviewer respectively. Hence, 3 intersections is at least 0, which makes A the answer.
A. 0
B. 2
C. 4
D. 5
E. 10
Attachment:
SET.jpg [ 7.15 KiB | Viewed 4753 times ]
