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FACTORISING 144 will give :
2*2*2*2*3* 3

if 2 numbers are to be multipled such that a* b = 144
HCF in this case could only be 6

Thus Ans : A
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Superb Question...
Absolutely Amazing ..
it tests all you know about LCM and HCF/GCD
Here LCM *GCD = product of 2 numbers and this property is satisfied by all the options
But don't be fooled here.
Remember => LCM entirely contains the GCD or in other words => GCD*P=LCM for some integer P
hence GCD must completely divide the LCM
hence A is Correct.
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Divyadisha
Is the answer 'E'. Product of any two numbers is equal to the product of LCM and HCF.

All the options satisfy this condition

Correct but can LCM/GCD not be an integer?
Remember we must always check both the properties.


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Properties of LCM and HCF

1) HCF*LCM=a*b
2) LCM= HCF*P (where p is some integer)
3) HCF of given fractions = HCF of numerator/LCM of denominator
4) LCM of given fraction = LCM of numerator/ HCF of denominator
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easy question product of two numbers = 144
hcf will be there in both numbers
eg suppose hcf is 2 for two numbers
then numbers would be in form 2*x ,2*y
only A satisfy the condition.
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First of all, only one is correct. Lets see how.
Given: Product of a*b= 144

option2, LCM= 18 HCF= 8
It is not possible as HCF is 2^3 but LCM contains only one 2.= 3^2*2= 18.

So now asking question that where got extra 2*2.

Similarly option 3, LCM= 2*2*2*2 and HCF is = 3*3
This can't be possible as LCM doesn't contain any 3.

So option 1 is only possible combination.

Very good learning from this problem.


Divyadisha
Is the answer 'E'. Product of any two numbers is equal to the product of LCM and HCF.

All the options satisfy this condition
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umber is 144.

No of factors are 5*3 = 15

Square of number is 12.

No of factors before 12 are 7 numbers and after 12 are 7 numbers

1,2,3,4,6,8,9,12,16,18,24,36,48,72,144

Therefore various combinations are
1*144 = 144
2*72 = 144
3*48=144
4*36=144
6*24=144
8*18=144
9*16=144

Among the above only option A is matching i.e. LCM 24 and HCF 6
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