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Bunuel
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It is basically asking what is the biggest 3 digit square number. Answer is 'E'

Tip- All squares have odd numbers of factors.
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All squares have odd number of factors.
Highest square 31^2 =961
Answer E
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Remember whenever the question says odd number odd number of factors we must conclude that its a perfect square.
Hence E is correct which is a perfect square of 31
hence E
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Bunuel
What is the largest 3 digit number to have an odd number of factors?

A. 625
B. 729
C. 841
D. 943
E. 961

A number greater than 1 will have an odd number of factors only if it's a perfect square. The largest 3-digit perfect square is 31 x 31 = 961 (since 32 x 32 = 1,024).

Answer: E
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Just a question: How is one suppose to mentally calculate/know for certain that the answer choices presented are all perfect squares?

Is it common to memorize Perfect Squares up to 30..etc?.. I feel this question would take me far too much time to assess whether each answer choice is a perfect square. The only one I know off the bat was 625..:/
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Bunuel
What is the largest 3 digit number to have an odd number of factors?

A. 625
B. 729
C. 841
D. 943
E. 961

Asked: What is the largest 3 digit number to have an odd number of factors?

Number having odd number of factors = square of integer
\(961 = 31^2\)

IMO E
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Remember whenever the question says odd number odd number of factors we must conclude that its a perfect square.
Hence E is correct which is a perfect square of 31
hence E


How can you infer that 961 is the square of 31?
Do you use prime factorization or what?
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What is the largest 3 digit number to have an odd number of factors?

A. 625
B. 729
C. 841
D. 943
E. 961

Square of prime numbers has 3 factors i.e odd no of factors. Since we are asked to find the largest 3 digit number with odd no of factors, let's start with
Option E . 961

961 = \(31^2\) and 31 is a prime number.
So 961 has 3 factors (ODD). Since 961 is the largest among the options, we don't need to look for other options.

Option E is the answer.

Thanks,
Clifin J Francis,
GMAT SME.
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