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Bunuel
If a and b are integers and (2^a)(3^b) is a factor of 100^40, what is the largest possible value of ab?

A. 0
B. 5
C. 20
D. 40
E. 80

Good one from Bunuel as usual

\(100^{40}\) = \(10^{80}\)

\(10^{80}\) = \({2*5}^{80}\)

From the above you get a = 80 ; but what about b ?

There is no 3 in 100^40 , so b will be 0

hence ab = 80*0 =>0

Answer will be (A)
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Bunuel
If a and b are integers and (2^a)(3^b) is a factor of 100^40, what is the largest possible value of ab?

A. 0
B. 5
C. 20
D. 40
E. 80

I am so careless.. ended up choosing E.

There are 80 multiples of 2 in 100^40 and 0 multiples of 3

so 0 * 80 = 0. i need to make sure I am answering the question!!!!
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(100)^40 = { (2)^2 * (5)^2 }^40 = ( 2^80 * 5^80)

Given,

2^a * 3^b is a factor of (100)^40 (= ( 2^80 * 5^80)). This is possible for a=80 and b=0.

Hence, a*b = 80*0 = 0

Answer: A
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