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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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Bunuel
From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.

Hi
the triangle formed is right angle triangle with two sides 1.2 *5 = 3*0.4 *5 and 4*0.4* 5 and these are in the ratio 3:4..
so we have a triangle in the ratio 3:4:5....and we have to find the HYP0 or ratio 5...
so it is \(5* 1.2 *\frac{5}{3} = 5*0.4*5 = 10\)
A
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Bunuel
From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.


After five hours,
At a 1.6km/h speed first competitor went=1.6*5=8km

and

At a 1.2/h speed second competitor went=1.2*5=6km

Since north and West are in \(90^{\circ}\) ,their Distance =\(\sqrt{8^2+6^2}\)=\(\sqrt{100}\)=10

Correct answer A
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Bunuel
From the starting point in a boat race, one competitor started to sail north at a speed of 1.6 Km/h, the other competitor started to sail west at a speed of 1.2 Km/h. What is the distance in Km between the two competitors after 5 hours?

A. 10.
B. 12.
C. 12.5.
D. 14.
E. 15.4.

The two competitors are sailing in perpendicular lines.
Hence the distance between the two would be the hypotenuse of the triangle formed.

Distance by competitor 1 = 1.6*5 = 8km
Distance by competitor 2 = 1.2*5 = 6km

Distance between the both = (64 + 36)^(1/2) = 10km

Correct Option: A
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Classic pythagoras problem using a bit of time-speed-distance
the person travelling north at rate of 1.6 km/hr for a period of 5 hrs travels 8 kms
the person travelling west at rate of 1.2 km/hr for a period of 5 hrs travels 6 kms

Distance between them can be given by \(8^2\) \(+\) \(6 ^2\) \(=\) \(10 ^2\)
taking positive square roots
so distance = 10 kms
Correct answer -\(A\)
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