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28 Dec 2016, 01:48
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
88% (00:49) correct
12%
(00:57)
wrong
based on 130
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If six marbles are being chosen from a jar of 27 different marbles to play a game. How many different sets of 6 can be chosen?
A. 27!
B. 27!/4!
C. 27!/6!
D. 27!/(21!4!)
E. 27!/(21!6!)
A. 27!
B. 27!/4!
C. 27!/6!
D. 27!/(21!4!)
E. 27!/(21!6!)
28 Dec 2016, 11:54
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Bunuel
\(27C_6 = \frac{27!}{(21!6!)}\)
Answer will be (E) \(\frac{27!}{(21!6!)}\)
20 Jan 2017, 09:48
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Choosing in a set do not have ordering. Choose \(6\) out of \(27\) :
\(27C6\)
\(\frac{27!}{21!6!}\)
\(27C6\)
\(\frac{27!}{21!6!}\)
