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Bunuel
At least how many grams of pure bronze must be alloyed with 387 grams of pure copper to create an alloy that is no more than 90% copper?

A. 13
B. 43
C. 103
D. 348
E. 430


SOLUTION:

the question stem means -> 387gms of copper is 90% of the alloy
Therefore 387=90/100*ALLOY

ALLOY=387*100/90=430GMS
BRONZE=430-387=43

ANS B
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Bunuel
At least how many grams of pure bronze must be alloyed with 387 grams of pure copper to create an alloy that is no more than 90% copper?

A. 13
B. 43
C. 103
D. 348
E. 430

let b=grams of bronze to be added
b=.10(387+b)
b=43
B
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At least how many grams of pure bronze must be alloyed with 387 grams of pure copper to create an alloy that is no more than 90% copper?

387 gram of pure copper should be no more than 90%.

If we consider 387 grams as 90% , then we get 10% as 387/9 = 43. We need 43 grams of pure bronze must be added.

Ans: B
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Bunuel
At least how many grams of pure bronze must be alloyed with 387 grams of pure copper to create an alloy that is no more than 90% copper?

A. 13
B. 43
C. 103
D. 348
E. 430

We can let n = the number of grams of pure bronze needed and create the equation:

387/(387 + n) = 9/10

3870 = 9(387 + n)

430 = 387 + n

43 = n

Alternate Solution:

We can let x = the total minimum weight of the alloy and create the equation:

0.9x = 387

9x = 3870

x = 3870/9

x = 430

Since the total minimum weight of the alloy must be 430 grams, we see that the minimum amount of bronze must be 430 - 387 = 43 grams.

Answer: B
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Bunuel
At least how many grams of pure bronze must be alloyed with 387 grams of pure copper to create an alloy that is no more than 90% copper?

A. 13
B. 43
C. 103
D. 348
E. 430


easy.
90% of total is copper which is 387, so total is 430, hence bronze should be 43.
asnwer 'B'
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