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13 May 2017, 14:26
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
82% (01:20) correct
18%
(01:56)
wrong
based on 222
sessions
History
Date
Time
Result
Not Attempted Yet
How many license plates are possible if the plate must contain exactly five digits, and the plate cannot start with 0 or repeat any digits? (The digits must be in a row and the plate contains no other characters.)
A. 8,238
B. 15,120
C. 27,216
D. 30,240
E. 59,049
A. 8,238
B. 15,120
C. 27,216
D. 30,240
E. 59,049
13 May 2017, 20:31
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Bunuel
The license plate forms as \(abcde\) with \(a \neq 0\)
With \(a\), we can select 9 different digits from 1 to 9.
With \(b\), we can select 9 remaining digits from 0 to 9 (1 digit is picked out with \(a\))
With \(c\), we can select 8 remaining digits from 0 to 9 (2 digits are picked out)
With \(d\), we can select 7 remaining digits from 0 to 9 (3 digits are picked out)
With \(e\), we can select 6 remaining digits from 0 to 9 (4 digits are picked out)
The total combination is \(9 \times 9 \times 8 \times 7 \times 6 =27,216\)
The answer is C.
13 May 2017, 20:38
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Bunuel
Hi...
Go stepwise and don't go wrong on the first step..
1) the first digit can be anything except 0, so 9 ways.
2) second can be remaining 8 from step 1 and 0, so 8+1=9 ways.
3) third digit remaining 8 from step 2... 8ways
4) fourth...7 ways
5) fifth....6 ways..
Total 9*9*8*7*6
Now the choices should help you..
Number should be EVEN but not multiple of 10.. ONLY A and C.
Number should be multiple of 9 .... Add the digits to find
A. 8238..8+2+3+8=21.... Not a multiple of 9... Out
C. 27,216....2+7+2+1+6=18..... Multiple of 9.. ANS
C
