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Time = X hrs and Y minutes or X hrs + Y/60 Hrs or (x+y/60) hrs
Distance = Z
Speed = D/T = Z/(x+y/60) = z/((60x+y)/60) = 60z/(60x+y)
So answer is B
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Bunuel
In x hours and y minutes a car traveled z miles. What is the car's speed in miles per hour?

(A) z/(60 + y)

(B) 60z/(60x + y)

(C) 60/(60 + y)

(D) z/(x + y)

(E) (60 + y)/60z

Let’s convert y minutes to hours.

y minutes = y/60 hours.

So, the car traveled for x + y/60 = 60x/60 + y/60 = (60x + y)/60 hours.

Since rate = distance/time, the rate is z/60x + y)/60 = 60z/(60x + y)

Answer: B
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Total Time in hours = x + y/60 = (60x+y)/60
Total Distance in miles = z

Car's Speed in miles per hours = z / [(60x+y)/60] = 60z/(60x+y)

Answer is B
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Bunuel
In x hours and y minutes a car traveled z miles. What is the car's speed in miles per hour?

(A) z/(60 + y)

(B) 60z/(60x + y)

(C) 60/(60 + y)

(D) z/(x + y)

(E) (60 + y)/60z
You can also choose values. I picked small value for x, 30 minutes for y to get a .5, and 9 for z because 9 is a multiple of 4.5

Let x = 4 hours
Let y = 30 minutes
Let z = 9 miles

Time = 4 hours and 30 minutes or 4.5 hours (it does not equal x + y -- that would be 34)

The car's speed in miles per hour is D/T, or 9 miles/4.5 hours = 2 miles per hour

Check each answer; the one that yields 2 with the assigned values is correct.

(A) z/(60 + y), without calculation, reject; fraction will be less than 1. Incorrect

(B) 60z/(60x + y), yields (60)(9)/270. Factor out 9 from numerator/denominator. 60/30 = 2 miles per hour. Correct.

(C) 60/(60 + y) - without calculating, reject; fraction will be less than 1. Incorrect.

(D) z/(x + y) - without calculating, reject. It's less than 1. It's the trap answer here, though. It yields 9/34, but would yield 9/4.5 if you mistakenly put converted y in. Incorrect.

(E) (60 + y)/60z - without calculating, reject. z is bigger than y; the denominator will be huge, the fraction, less than 1. Incorrect.

Answer B
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Rate=Dist/time
R=z/(x+y/60)
=60z/(60x+y)
Hence, B

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