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Bunuel
Let P = (x + y)k. If P = 10 and k = 3, what is the average of x and y?

(A) 0
(B) 1/2
(C) 5/3
(D) 10/3
(E) 7/2

We are given that P = (x + y)k, P = 10, and k = 3. Thus:

10 = (x + y)3

10/3 = x + y

Since x + y = 10/3, the average of x and y is (x +y)/2 = (10/3)/2 = 10/6 = 5/3.

Answer: C
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Bunuel
Let P = (x + y)k. If P = 10 and k = 3, what is the average of x and y?

(A) 0
(B) 1/2
(C) 5/3
(D) 10/3
(E) 7/2

On substituting the values of P and k, we get:

10 = (x+y)*3
Or, (x + y) = 10/3

Hence average of x and y = (x+y)/ 2 = (10/3)/2 = 5/3

Correct Option: C
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