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MathRevolution
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MathRevolution
\(√m^4=64\) and m>0, what is the value of cubic root of m?

A. 1
B. 2
C. 4
D. 8
E. 16

\(\sqrt{m^{4}} = 64.\)
Squaring on both sides, we get \(m^{4} = 64^{2}\)
So, \(m^{2} = 64\), hence, \(m = 8\) (given: \(m > 0\))

Cube root of 8 = 2. Ans - B.
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MathRevolution
\(√m^4=64\) and m>0, what is the value of cubic root of m?

A. 1
B. 2
C. 4
D. 8
E. 16

\(\sqrt{m^4}=64\)

\(m^{\frac{4}{2}}\) \(= 64\)

\(m^2 = 64\)

\(m = +8\) or \(-8\)

Given \(m>0\).

Therefore; \(m = 8\)

We need to find the value of Cubic root of \(m\)

\(\sqrt[3]{m} = \sqrt[3]{8} = 2\)

Answer (B)...

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MathRevolution
\(√m^4=64\) and m>0, what is the value of cubic root of m?

A. 1
B. 2
C. 4
D. 8
E. 16

\(√m^4=64\)

So, \(√m^2=8^2\)

Or, \(m = 8\)

Hence, \(^3√m=2\)

Thus, answer will be (B) 2
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==> You get \(√m^4=64=2^6, m^4=(2^6)^2=2^{12}.\) Then, you get \(m=(2^{12})^{\frac{1}{4}}=2^3\), and from 3√m=3\(\sqrt{2^3}\)=2, the answer is B.

Answer: B
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MathRevolution
\(√m^4=64\) and m>0, what is the value of cubic root of m?

A. 1
B. 2
C. 4
D. 8
E. 16

Let’s solve for m:

√(m^4) = 64

(m^4)^(½) = 64

m^2 = 64

|m| = √64

|m| = 8

m = 8 or m = -8

Since m > 0, m = 8.

Thus, the cube root of m is 2.

Answer: B
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