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Bunuel
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Bunuel
Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?


I. The average of Set T is 60.

II. The range of Set T is greater than that of Set S.

III. x is an even number


(A) I only

(B) I & II

(C) II only

(D) I & III

(E) All of the above

S & T both contains x elements.
Av.(Set S) = 40
Sum (Set S) = 40x

Av.(Set S & T) = 50
Sum (Set S & T) = 100x

So Sum of Set T = 60x
Av(Set T) = 60

I. CORRECT

II. The Least and highest numbers in set S may be ( -30, 90) and Set T may be (60,60). SO we can't comment on the value of range.
INCORRECT

III. Since x has no role in finding the average values etc. So, we can't say x is even or not.
INCORRECT


Answer A
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GMAT Focus 1: 735 Q90 V89 DI81
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Bunuel
Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?


I. The average of Set T is 60.

II. The range of Set T is greater than that of Set S.

III. x is an even number


(A) I only

(B) I & II

(C) II only

(D) I & III

(E) All of the above

S & T both contains x elements.
Av.(Set S) = 40
Sum (Set S) = 40x

Av.(Set S & T) = 50
Sum (Set S & T) = 100x

So Sum of Set T = 60x
Av(Set T) = 60

I. CORRECT

II. The Least and highest numbers in set S may be ( -30, 90) and Set T may be (60,60). SO we can't comment on the value of range.
INCORRECT

III. Since x has no role in finding the average values etc. So, we can't say x is even or not.
INCORRECT


Answer A

hi,

just on a lighter side..

your signature says " Appreciate by clicking +1 kudos (lets be generous, friends)"
so instinctively thought of looking at your \(\frac{kudos.given}{kudos.recieved}\)..
it is less than \(\frac{1}{2}\).. remembered a proverb -- " Charity begins at home" :wink:
On the lighter side. will remove it if offended
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Bunuel
Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?


I. The average of Set T is 60.

II. The range of Set T is greater than that of Set S.

III. x is an even number


(A) I only

(B) I & II

(C) II only

(D) I & III

(E) All of the above



    • Let the average be Set T be “T”.
      o Average of S and T \(= \frac{(Tx + 40x)}{2x}\)
      o \(100 = T + 40\)
      o Thus, \(T = 60\)
      o Statement I is correct.

    • Let us now focus on the Range.
      o Set S average is 40.
      o A possible scenario could be {40,40,40….x terms), the range is 0 in this case.
      o Set T average is 60.
      o A possible scenario could be {60, 60,60….x terms), the range is 0 in this case.
        • Thus, we cannot say for sure if the range of Set T is greater than Set S.
      o Statement II is not always true.
    • Finally, we do not know the value of x, it could be even or odd.

Thus, the correct answer is Option A.


Thanks,
Saquib
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chetan2u
shashankism
Bunuel
Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?


I. The average of Set T is 60.

II. The range of Set T is greater than that of Set S.

III. x is an even number


(A) I only

(B) I & II

(C) II only

(D) I & III

(E) All of the above

S & T both contains x elements.
Av.(Set S) = 40
Sum (Set S) = 40x

Av.(Set S & T) = 50
Sum (Set S & T) = 100x

So Sum of Set T = 60x
Av(Set T) = 60

I. CORRECT

II. The Least and highest numbers in set S may be ( -30, 90) and Set T may be (60,60). SO we can't comment on the value of range.
INCORRECT

III. Since x has no role in finding the average values etc. So, we can't say x is even or not.
INCORRECT


Answer A

hi,

just on a lighter side..

your signature says " Appreciate by clicking +1 kudos (lets be generous, friends)"
so instinctively thought of looking at your \(\frac{kudos.given}{kudos.recieved}\)..
it is less than \(\frac{1}{2}\).. remembered a proverb -- " Charity begins at home" :wink:
On the lighter side. will remove it if offended

Hahahaha... chetan2u Yes you are correct but presently I am continuously in Kudos collection mode and trying to provide solution of as many questions as possible. So if you can see I am working very hard to solve & provide better solution to quant questions which is my strong area. Meanwhile when I get a good solution I too provide kudos. Once I will start solving VA section, in which I am weaker than QA section, I will surely provide kudos to good answers. But for last 1 month I am just solving and providing solution.. Anyway your comments are always welcome, it will increase bond between us and will help gmatclub to be more interactive. Even my moto is to interact with as many nice people here as possible :)
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Bunuel
Set S and Set T both contain x elements. The average of Set S is 40. If the average of Set S and Set T combined is 50, which of the following must be true?


I. The average of Set T is 60.

II. The range of Set T is greater than that of Set S.

III. x is an even number


(A) I only

(B) I & II

(C) II only

(D) I & III

(E) All of the above


Total of S = 40x
Total of S & T combined = 100x (50*2x)
Total of T = 60x
Average in T = 60x/x = 60

I must be true

Let x be odd
S = 30,40,50
Range of S = 20
T = 60,60,60
Average of S & T combined = 50
Range of T = 0

II and III not necessarily be true
Hence A
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