A manager must select 2 people from a group of 4 employees. One person

Question

A manager must select 2 people from a group of 4 employees. One person will be the shop steward and the other person will be the treasurer. In how many different ways can this be accomplished?

(A) 2

(B) 6

(C) 8

(D) 12

(E) 16

kunalsinghNS · Answer

4C2 = 6

Hence total possible ways of selection = 6

Luckisnoexcuse · Answer

4C2 * 2 = 6 * 2 = 12
4C2 for selection and multiplication by 2 for allocation
D

Madhavi1990 · Answer

12--> 6 ways to select and 2 ways to shuffle
What is OA?

kumarparitosh123 · Answer

Mine approach would be the same as yours.
OA ???

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Bunuel · Answer

The OA will be automatically revealed on Thursday 24th of August 2017 01:18:15 AM Pacific Time Zone

niks18 · Answer

Here we need to assign / arrange  2  people out of  4  people to  2  posts.

This can be done is  4_P_2  ways  = 12

Option  D

habdo · Answer

Why combination and not permutation

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AliciaSierra · Answer

Approach could be first select two person out of 4 and then arrange them.

Select 2 person out of 4 people=  4C2 
number of ways to arrange two selected person into 2 positions =2

Answer would be 4C2*2= 12

IMO:D

sarbjeetsingh777 · Answer

Hello 
Out of 4 people, 2 people can be selected in 4C2 number of ways 
also, two persons selected for two positions can be shuffled in 2! ways as A-B, B-A
So total number of ways = 4C2*2! = 6*2 = 12
Hence Option D

Macintosh1402 · Answer

Ans - D
Easy way:
Assume that there are 2 slots to be filled, S-Steward and T-Treasurer
For S - You have 4 people to chose from
Once, S is selected, for T, you are left with 3 people to chose from

So, total options - 4x3 = 12

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manishgmat1 · Answer

selection one 1 out of 4
4 ways 
selection 1 out of 3
3 ways 
total 4*3=12

ankita09 · Answer

D) 12
total number of way for selecting 2 out of 4 = 4c1 * 3c1= 4*3 =12

AqsaGhori · Answer

Option:D
For position 1
4 choices we have
for position 2
3 choices we have
4*3=
12

ScottTargetTestPrep · Answer

Since we have specific positions in the group, order matters, and so we have a permutation. Thus, the number of ways to select a steward and a treasurer from 4 employees is 4P2 = 4!/2! = 4 x 3 = 12 ways.

Answer: D

MishalSen · Answer

Selecting steward: 4!/1!*3! = 4
Selecting treasurer: 3!/1!*2! = 3

Selecting Steward AND Treasurer : 4*3=12

IMO Ans: D

AnirudhaS · Answer

4*3=12

Answer:  D

A manager must select 2 people from a group of 4 employees. One person

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A manager must select 2 people from a group of 4 employees. One person

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