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27 Sep 2017, 04:50
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A
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If the length and width of rectangle A are 10 percent less and 30 percent less respectively than the length and width of rectangle B, the area of A is equal to what percent of the area of B?
(A) 63%
(B) 60%
(C) 40%
(D) 6%
(E) 3%
(A) 63%
(B) 60%
(C) 40%
(D) 6%
(E) 3%
27 Sep 2017, 06:44
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Let length and width of the rectangle B are X and Y .
So area of rectangle B is XY.
From given data we get length and rectangle of rectangle A are 0.9X and 0.7Y
So area of rectangke A is 0.63XY
Percentage of Area of rectangle A / Area of rectangle B = (0.63XY/XY )*100 = 63%
So area of rectangle B is XY.
From given data we get length and rectangle of rectangle A are 0.9X and 0.7Y
So area of rectangke A is 0.63XY
Percentage of Area of rectangle A / Area of rectangle B = (0.63XY/XY )*100 = 63%
27 Sep 2017, 10:34
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If the length and width of rectangle A are 10 percent less and 30 percent less respectively than the length and width of rectangle B, the area of A is equal to what percent of the area of B?
Let measurement of rectangle B = l*b
Measurement of A => 10% less of l and 30% less of b = 0.9l & 0.7b
Area of A = 0.9l * 0.7b = 0.63 l*b = 0.63 * Area of B
=> Area of A is 63 % of area of B
Answer: A
Let measurement of rectangle B = l*b
Measurement of A => 10% less of l and 30% less of b = 0.9l & 0.7b
Area of A = 0.9l * 0.7b = 0.63 l*b = 0.63 * Area of B
=> Area of A is 63 % of area of B
Answer: A
