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11 Oct 2017, 00:49
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In the figure above, if two identical rectangles overlap to form three regions with areas 12, 6, and R, respectively, then R =
(A) 6
(B) 12
(C) 15
(D) 18
(E) 24
Attachment:
2017-10-11_1127_001.png [ 3.86 KiB | Viewed 4392 times ]
11 Oct 2017, 01:18
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Assuming that y is the total length of rectangle and not of each smaller rectangle.
xy=12+6=18
Also, xy=R+6
Therefore, R+6=18
R=12
Answer B.
xy=12+6=18
Also, xy=R+6
Therefore, R+6=18
R=12
Answer B.
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11 Oct 2017, 08:01
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This seems too easy...am I missing something here? 
Since the rectangles are identical, and assuming the region with area 6 does not overlap region with areas 12 or R:
Area of both rectangles will be equal
R + 6 = 12 + 6
R = 12
Since the rectangles are identical, and assuming the region with area 6 does not overlap region with areas 12 or R:
Area of both rectangles will be equal
R + 6 = 12 + 6
R = 12
